From df0bb71bce1bc76c5ebe3021b59a99b2f77d587d Mon Sep 17 00:00:00 2001
From: KevinatorTrainer5 <44285042+KevinatorTrainer5@users.noreply.github.com>
Date: Thu, 22 Nov 2018 01:52:03 +1100
Subject: [PATCH] Elaboration of unknown side cases on Pythagoras Theorem
 (#22373)

-I decided to extend the amount of information on Pythagoras Theorem, through explaining other cases of finding an unknown side apart from the hypotenuse, which are the perpendicular height and base.
---
 .../mathematics/pythagorean-theorem/index.md  | 24 +++++++++++++++++++
 1 file changed, 24 insertions(+)

diff --git a/guide/english/mathematics/pythagorean-theorem/index.md b/guide/english/mathematics/pythagorean-theorem/index.md
index ef353f9c50..42495c1227 100644
--- a/guide/english/mathematics/pythagorean-theorem/index.md
+++ b/guide/english/mathematics/pythagorean-theorem/index.md
@@ -13,7 +13,31 @@ The theorem states:
 
 c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup>
 
+c = &radic;(a<sup>2</sup> + b <sup>2</sup>), where c > 0
+
 Whenever you are given two sides of a right triangle, you can calculate the third one using the Pythagorean Theorem.
 
+In some instances, the value of the perpendicular height or the base may not be given, but the value of the hypotenuse can be given. So in this case: 
+
+Let c become the length of the hypotenuse, a become the length of the perpendicular, and b become the length of the height. The Pythagoras Theorem is given by:
+
+a<sup>2</sup> + b<sup>2</sup> = c<sup>2</sup>
+
+The first case will be finding the unknown value of the perpendicular height, which is 'a'. So firstly, we will make a<sup>2</sup> become the subject:
+
+a<sup>2</sup> = c<sup>2</sup> - b<sup>2</sup>
+
+And then, we will square root both sides to get the value of a:
+
+a = &radic;(c<sup>2</sup> - b<sup>2</sup>)
+
+For the second case, we will be finding the unknown value of the base, which is 'b'. So we will firstly make b<sup>2</sup> become the subject:
+
+b<sup>2</sup> = c<sup>2</sup> - a<sup>2</sup>
+
+And then, we will square root both sides to get the value of b:
+
+b = &radic;(c<sup>2</sup> - a<sup>2</sup>)
+
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