chore(i8n,learn): processed translations

curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-112-bouncy-numbers.md

@@ -1,18 +1,28 @@
 ---
 id: 5900f3dd1000cf542c50feef
-title: 问题112：有弹性的数字
+title: 'Problem 112: Bouncy numbers'
 challengeType: 5
-videoUrl: ''
+forumTopicId: 301738
 dashedName: problem-112-bouncy-numbers
 ---
 
 # --description--
 
-如果左边的数字没有超过数字，则从左到右工作，称为递增数字;例如，134468。同样，如果右边的数字没有超过数字，则称为递减数字;例如，66420。我们将调用一个既不增加也不减少“有弹性”数的正整数;例如，155349。显然，不会有任何低于一百的弹性数字，但只有超过一千（525）的数字超过一半是有弹性的。事实上，有弹性数字首次达到50％的最小数量是538.令人惊讶的是，有弹性的数字变得越来越普遍，当我们达到21780时，有弹性数字的比例等于90％。找出有弹性数字的比例正好为99％的最小数字。
+Working from left-to-right if no digit is exceeded by the digit to its left it is called an increasing number; for example, 134468.
+
+Similarly if no digit is exceeded by the digit to its right it is called a decreasing number; for example, 66420.
+
+We shall call a positive integer that is neither increasing nor decreasing a "bouncy" number; for example, 155349.
+
+Clearly there cannot be any bouncy numbers below one-hundred, but just over half of the numbers below one-thousand (525) are bouncy. In fact, the least number for which the proportion of bouncy numbers first reaches 50% is 538.
+
+Surprisingly, bouncy numbers become more and more common and by the time we reach 21780 the proportion of bouncy numbers is equal to 90%.
+
+Find the least number for which the proportion of bouncy numbers is exactly 99%.
 
 # --hints--
 
-`euler112()`应返回1587000。
+`euler112()` should return 1587000.
 
 ```js
 assert.strictEqual(euler112(), 1587000);