chore(i8n,learn): processed translations

curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-243-resilience.md

@@ -1,22 +1,24 @@
 ---
 id: 5900f4601000cf542c50ff73
-title: 问题243：恢复力
+title: 'Problem 243: Resilience'
 challengeType: 5
-videoUrl: ''
+forumTopicId: 301890
 dashedName: problem-243-resilience
 ---
 
 # --description--
 
-分子小于其分母的正分数称为适当分数。对于任何分母，d，将有d-1个适当的分数;例如，d = 12：1 / 12,2 / 12,3 / 12,4 / 12,5 / 12,6 / 12,7 / 12,8 / 12,9 / 12,10 / 12,11 / 12。
+A positive fraction whose numerator is less than its denominator is called a proper fraction.
 
-我们将称一个无法取消弹性部分的分数。此外，我们将分母R（d）的弹性定义为具有弹性的适当分数的比率;例如，R（12）= 4/11。事实上，d = 12是具有弹性R（d）<4/10的最小分母。
+For any denominator, d, there will be d−1 proper fractions; for example, with d = 12:1/12 , 2/12 , 3/12 , 4/12 , 5/12 , 6/12 , 7/12 , 8/12 , 9/12 , 10/12 , 11/12 .
 
-找到最小分母d，具有弹性R（d）<15499/94744。
+We shall call a fraction that cannot be cancelled down a resilient fraction. Furthermore we shall define the resilience of a denominator, R(d), to be the ratio of its proper fractions that are resilient; for example, R(12) = 4/11 . In fact, d = 12 is the smallest denominator having a resilience R(d) < 4/10 .
+
+Find the smallest denominator d, having a resilience R(d) < 15499/94744 .
 
 # --hints--
 
-`euler243()`应该返回892371480。
+`euler243()` should return 892371480.
 
 ```js
 assert.strictEqual(euler243(), 892371480);