chore(i8n,learn): processed translations

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---
id: 5900f4b11000cf542c50ffc4
title: 问题325石头游戏II
title: 'Problem 325: Stone Game II'
challengeType: 5
videoUrl: ''
forumTopicId: 301982
dashedName: problem-325-stone-game-ii
---
# --description--
一场比赛是用两堆石头和两个球员进行的。在轮到她时,玩家从较大的堆中移除了许多石头。她移除的石头数量必须是较小桩中石头数量的正数倍。
A game is played with two piles of stones and two players. At her turn, a player removes a number of stones from the larger pile. The number of stones she removes must be a positive multiple of the number of stones in the smaller pile.
例如让有序对6,14描述一个配置在较小的桩中有6个石头在较大的桩中有14个石头那么第一个玩家可以从较大的桩中移除6或12个石头。
E.g., let the ordered pair(6,14) describe a configuration with 6 stones in the smaller pile and 14 stones in the larger pile, then the first player can remove 6 or 12 stones from the larger pile.
从一堆中取出所有宝石的玩家赢得比赛。
The player taking all the stones from a pile wins the game.
获胜配置是第一个玩家可以强制获胜的配置。例如1,52,63,12是获胜配置因为第一个玩家可以立即移除第二堆中的所有宝石。
A winning configuration is one where the first player can force a win. For example, (1,5), (2,6) and (3,12) are winning configurations because the first player can immediately remove all stones in the second pile.
失败的配置是第二个玩家可以强制获胜的配置无论第一个玩家做什么。例如2,33,4正在失去配置任何合法移动都会为第二个玩家留下获胜配置。
A losing configuration is one where the second player can force a win, no matter what the first player does. For example, (2,3) and (3,4) are losing configurations: any legal move leaves a winning configuration for the second player.
将SN定义为所有丢失配置xiyi的总和xi + yi0 <xi <yi≤N。我们可以验证S10= 211和S104= 230312207313
Define S(N) as the sum of (xi+yi) for all losing configurations (xi,yi), 0 < xi < yi ≤ N. We can verify that S(10) = 211 and S(104) = 230312207313.
找到S1016mod 710
Find S(1016) mod 710.
# --hints--
`euler325()`应该返回54672965
`euler325()` should return 54672965.
```js
assert.strictEqual(euler325(), 54672965);