chore(i8n,learn): processed translations

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---
id: 5900f4c71000cf542c50ffd8
title: 问题346强大的Repunits
title: 'Problem 346: Strong Repunits'
challengeType: 5
videoUrl: ''
forumTopicId: 302005
dashedName: problem-346-strong-repunits
---
# --description--
数字7是特殊的因为7是用基数2写的111用基数6写的是11即710 = 116 = 1112。换句话说7是至少两个碱基b> 1的重新排列。
The number 7 is special, because 7 is 111 written in base 2, and 11 written in base 6 (i.e. 710 = 116 = 1112). In other words, 7 is a repunit in at least two bases b > 1.
我们将调用一个正整数该属性是一个强大的repunit。可以证实在50以下有8个强大的重新命令{1,7,13,15,21,31,40,43}。此外1000以下的所有强大的重新命令的总和等于15864
We shall call a positive integer with this property a strong repunit. It can be verified that there are 8 strong repunits below 50: {1,7,13,15,21,31,40,43}. Furthermore, the sum of all strong repunits below 1000 equals 15864.
找出1012以下所有强大的回购总和。
Find the sum of all strong repunits below 1012.
# --hints--
`euler346()`应该返回336108797689259260
`euler346()` should return 336108797689259260.
```js
assert.strictEqual(euler346(), 336108797689259260);