chore(i8n,learn): processed translations

curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/accumulator-factory.md

@@ -1,36 +1,48 @@
 ---
 id: 594810f028c0303b75339ace
-title: 蓄能器工厂
+title: Accumulator factory
 challengeType: 5
-videoUrl: ''
+forumTopicId: 302222
 dashedName: accumulator-factory
 ---
 
 # --description--
 
-<p>创建一个带有单个（数字）参数的函数，并返回另一个作为累加器的函数。返回的累加器函数又接受一个数字参数，并返回到目前为止传递给该累加器的所有数值的总和（包括创建累加器时传递的初始值）。 </p><p>规则： </p><p>不要使用全局变量。 </p><p>暗示： </p><p>闭包可以保存外部状态。 </p>
+A problem posed by [Paul Graham](https://en.wikipedia.org/wiki/Paul_Graham_(programmer)) is that of creating a function that takes a single (numeric) argument and which returns another function that is an accumulator. The returned accumulator function in turn also takes a single numeric argument, and returns the sum of all the numeric values passed in so far to that accumulator (including the initial value passed when the accumulator was created).
+
+# --instructions--
+
+Create a function that takes a number $n$ and generates accumulator functions that return the sum of every number ever passed to them.
+
+**Rules:**
+
+Do not use global variables.
+
+**Hint:**
+
+Closures save outer state.
 
 # --hints--
 
-`accumulator`是一个功能。
+`accumulator` should be a function.
 
 ```js
 assert(typeof accumulator === 'function');
 ```
 
-`accumulator(0)`应该返回一个函数。
+`accumulator(0)` should return a function.
 
 ```js
 assert(typeof accumulator(0) === 'function');
 ```
 
-`accumulator(0)(2)`应该返回一个数字。
+`accumulator(0)(2)` should return a number.
 
 ```js
 assert(typeof accumulator(0)(2) === 'number');
 ```
 
-传递值3，-4,1.5和5应返回5.5。
+Passing in the values 3, -4, 1.5, and 5 should return 5.5.
 
 ```js
 assert(testFn(5) === 5.5);