chore(i8n,learn): processed translations

curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/day-of-the-week.md

@@ -1,36 +1,40 @@
 ---
 id: 5966f99c45e8976909a85575
-title: 一周中的天
+title: Day of the week
 challengeType: 5
-videoUrl: ''
+forumTopicId: 302245
 dashedName: day-of-the-week
 ---
 
 # --description--
 
-<p>一家公司决定，每当圣诞节落在星期天，他们将给予他们的工人所有额外带薪假期，这样，在任何公共假期，工人将不必在下一周（12月25日到1月1日之间）工作。 </p><p>任务： </p><p>编写一个开始年份和结束年份的函数，并返回12月25日为星期日的所有年份的数组。 </p>
+A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
+
+# --instructions--
+
+Write a function that takes a start year and an end year and return an array of all the years where the 25th of December will be a Sunday.
 
 # --hints--
 
-`findXmasSunday`是一个函数。
+`findXmasSunday` should be a function.
 
 ```js
 assert(typeof findXmasSunday === 'function');
 ```
 
-`findChristmasSunday(2000, 2100)`应该返回一个数组。
+`findXmasSunday(2000, 2100)` should return an array.
 
 ```js
 assert(typeof findXmasSunday(2000, 2100) === 'object');
 ```
 
-`findChristmasSunday(2008, 2121`应该回归[1977,1983,1988,1994,2005,2011,2016]
+`findXmasSunday(1970, 2017)` should return `[1977, 1983, 1988, 1994, 2005, 2011, 2016]`
 
 ```js
 assert.deepEqual(findXmasSunday(1970, 2017), firstSolution);
 ```
 
-`findChristmasSunday(2008, 2121`应该返回[2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]
+`findXmasSunday(2008, 2121)` should return `[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]`
 
 ```js
 assert.deepEqual(findXmasSunday(2008, 2121), secondSolution);