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curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/equilibrium-index.md
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---
id: 5987fd532b954e0f21b5d3f6
title: 均衡指数
title: Equilibrium index
challengeType: 5
videoUrl: ''
forumTopicId: 302255
dashedName: equilibrium-index
---
# --description--
<p>序列的平衡指数是序列的索引，使得较低指数处的元素之和等于较高指数处的元素之和。 </p><p>例如，在序列<big>$ A $中</big> ： </p><p> :::: <big>$ A_0 = -7 $</big> </p><p> :::: <big>$ A_1 = 1 $</big> </p><p> :::: <big>$ A_2 = 5 $</big> </p><p> :::: <big>$ A_3 = 2 $</big> </p><p> :::: <big>$ A_4 = -4 $</big> </p><p> :::: <big>$ A_5 = 3 $</big> </p><p> :::: <big>$ A_6 = 0 $</big> </p><p> 3是均衡指数，因为： </p><p> :::: <big>$ A_0 + A_1 + A_2 = A_4 + A_5 + A_6 $</big> </p><p> 6也是均衡指数，因为： </p><p> :::: <big>$ A_0 + A_1 + A_2 + A_3 + A_4 + A_5 = 0 $</big> </p><p> （零元素之和为零） </p><p> 7不是均衡指数，因为它不是序列<big>$ A $</big>的有效索引。 </p><p>编写一个函数，给定一个序列，返回其平衡指数（如果有的话）。 </p><p>假设序列可能很长。 </p>
An equilibrium index of a sequence is an index into the sequence such that the sum of elements at lower indices is equal to the sum of elements at higher indices.
For example, in a sequence $A$:
<ul style='list-style: none;'>
<li><big>$A_0 = -7$</big></li>
<li><big>$A_1 = 1$</big></li>
<li><big>$A_2 = 5$</big></li>
<li><big>$A_3 = 2$</big></li>
<li><big>$A_4 = -4$</big></li>
<li><big>$A_5 = 3$</big></li>
<li><big>$A_6 = 0$</big></li>
</ul>
`3` is an equilibrium index, because:
<ul style='list-style: none;'>
<li><big>$A_0 + A_1 + A_2 = A_4 + A_5 + A_6$</big></li>
</ul>
`6` is also an equilibrium index, because:
<ul style='list-style: none;'>
<li><big>$A_0 + A_1 + A_2 + A_3 + A_4 + A_5 = 0$</big></li>
</ul>
(sum of zero elements is zero)
`7` is not an equilibrium index, because it is not a valid index of sequence $A$.
# --instructions--
Write a function that, given a sequence, returns its equilibrium indices (if any).
Assume that the sequence may be very long.
# --hints--
`equilibrium`是一种功能。
`equilibrium` should be a function.
```js
assert(typeof equilibrium === 'function');
```
`equilibrium([-7, 1, 5, 2, -4, 3, 0])` `[3,6]` `equilibrium([-7, 1, 5, 2, -4, 3, 0])`应该返回`[3,6]` 。
`equilibrium([-7, 1, 5, 2, -4, 3, 0])` should return `[3,6]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[0]), ans[0]);
```
`equilibrium([2, 4, 6])`应该返回`[]` 。
`equilibrium([2, 4, 6])` should return `[]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[1]), ans[1]);
```
`equilibrium([2, 9, 2])`应该返回`[1]` 。
`equilibrium([2, 9, 2])` should return `[1]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[2]), ans[2]);
```
`equilibrium([1, -1, 1, -1, 1, -1, 1])`应该返回`[0,1,2,3,4,5,6]` 。
`equilibrium([1, -1, 1, -1, 1, -1, 1])` should return `[0,1,2,3,4,5,6]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[3]), ans[3]);
```
`equilibrium([1])`应该返回`[0]` 。
`equilibrium([1])` should return `[0]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[4]), ans[4]);
```
`equilibrium([])`应该返回`[]` 。
`equilibrium([])` should return `[]`.
```js
assert.deepEqual(equilibrium(equilibriumTests[5]), ans[5]);