chore(i8n,learn): processed translations

curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/iterated-digits-squaring.md

@@ -1,67 +1,68 @@
 ---
 id: 5a23c84252665b21eecc7ec1
-title: 迭代的数字平方
+title: Iterated digits squaring
 challengeType: 5
-videoUrl: ''
+forumTopicId: 302291
 dashedName: iterated-digits-squaring
 ---
 
 # --description--
 
-如果添加自然数（大于零的整数）的数字的平方，则始终以1或89结尾：
+If you add the square of the digits of a Natural number (an integer bigger than zero), you always end with either 1 or 89:
 
-```
- 15  - > 26  - > 40  - > 16  - > 37  - > 58  - > 89
-7  - > 49  - > 97  - > 130  - > 10  - > 1 
-```
+<pre>15 -> 26 -> 40 -> 16 -> 37 -> 58 -> 89
+7 -> 49 -> 97 -> 130 -> 10 -> 1
+</pre>
 
-编写一个函数，该函数将数字作为参数，并在执行上述过程后返回1或89。
+# --instructions--
+
+Write a function that takes a number as a parameter and returns 1 or 89 after performing the mentioned process.
 
 # --hints--
 
-`iteratedSquare`应该是一个函数。
+`iteratedSquare` should be a function.
 
 ```js
 assert(typeof iteratedSquare == 'function');
 ```
 
-`iteratedSquare(4)`应该返回一个数字。
+`iteratedSquare(4)` should return a number.
 
 ```js
 assert(typeof iteratedSquare(4) == 'number');
 ```
 
-`iteratedSquare(4)`应该返回`89` 。
+`iteratedSquare(4)` should return `89`.
 
 ```js
 assert.equal(iteratedSquare(4), 89);
 ```
 
-`iteratedSquare(7)`应该返回`1` 。
+`iteratedSquare(7)` should return `1`.
 
 ```js
 assert.equal(iteratedSquare(7), 1);
 ```
 
-`iteratedSquare(15)`应该返回`89` 。
+`iteratedSquare(15)` should return `89`.
 
 ```js
 assert.equal(iteratedSquare(15), 89);
 ```
 
-`iteratedSquare(20)`应该返回`89` 。
+`iteratedSquare(20)` should return `89`.
 
 ```js
 assert.equal(iteratedSquare(20), 89);
 ```
 
-`iteratedSquare(70)`应该返回`1` 。
+`iteratedSquare(70)` should return `1`.
 
 ```js
 assert.equal(iteratedSquare(70), 1);
 ```
 
-`iteratedSquare(100)`应该返回`1` 。
+`iteratedSquare(100)` should return `1`.
 
 ```js
 assert.equal(iteratedSquare(100), 1);