chore(i8n,learn): processed translations

curriculum/challenges/espanol/10-coding-interview-prep/project-euler/problem-30-digit-n-powers.md

@@ -0,0 +1,74 @@
+---
+id: 5900f38a1000cf542c50fe9d
+title: 'Problem 30: Digit n powers'
+challengeType: 5
+forumTopicId: 301953
+dashedName: problem-30-digit-n-powers
+---
+
+# --description--
+
+Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits:
+
+<div style='margin-left: 4em;'>
+  1634 = 1<sup>4</sup> + 6<sup>4</sup> + 3<sup>4</sup> + 4<sup>4</sup><br>
+  8208 = 8<sup>4</sup> + 2<sup>4</sup> + 0<sup>4</sup> + 8<sup>4</sup><br>
+  9474 = 9<sup>4</sup> + 4<sup>4</sup> + 7<sup>4</sup> + 4<sup>4</sup><br>
+</div>
+
+As 1 = 1<sup>4</sup> is not a sum it is not included.
+
+The sum of these numbers is 1634 + 8208 + 9474 = 19316.
+
+Find the sum of all the numbers that can be written as the sum of `n` powers of their digits.
+
+# --hints--
+
+`digitnPowers(2)` should return a number.
+
+```js
+assert(typeof digitnPowers(2) === 'number');
+```
+
+`digitnPowers(2)` should return 0.
+
+```js
+assert(digitnPowers(2) == 0);
+```
+
+`digitnPowers(3)` should return 1301.
+
+```js
+assert(digitnPowers(3) == 1301);
+```
+
+`digitnPowers(4)` should return 19316.
+
+```js
+assert(digitnPowers(4) == 19316);
+```
+
+`digitnPowers(5)` should return 443839.
+
+```js
+assert(digitnPowers(5) == 443839);
+```
+
+# --seed--
+
+## --seed-contents--
+
+```js
+function digitnPowers(n) {
+
+  return n;
+}
+
+digitnPowers(5);
+```
+
+# --solutions--
+
+```js
+// solution required
+```