chore(i8n,learn): processed translations
This commit is contained in:
committed by
Mrugesh Mohapatra
parent
15047f2d90
commit
e5c44a3ae5
@ -0,0 +1,64 @@
|
||||
---
|
||||
id: 5900f3b11000cf542c50fec4
|
||||
title: 'Problem 69: Totient maximum'
|
||||
challengeType: 5
|
||||
forumTopicId: 302181
|
||||
dashedName: problem-69-totient-maximum
|
||||
---
|
||||
|
||||
# --description--
|
||||
|
||||
Euler's Totient function, φ(`n`) \[sometimes called the phi function], is used to determine the number of numbers less than `n` which are relatively prime to `n`. For example, as 1, 2, 4, 5, 7, and 8, are all less than nine and relatively prime to nine, φ(9)=6.
|
||||
|
||||
<div style='margin-left: 4em;'>
|
||||
|
||||
| !!crwdBlockTags_15_sgaTkcolBdwrc!! | Relatively Prime | φ(!!crwdBlockTags_16_sgaTkcolBdwrc!!) |!!crwdBlockTags_17_sgaTkcolBdwrc!!/φ(!!crwdBlockTags_18_sgaTkcolBdwrc!!) |
|
||||
| ------------ | ---------------- | --------------- | ---------------------------- |
|
||||
| 2 | 1 | 1 | 2 |
|
||||
| 3 | 1,2 | 2 | 1.5 |
|
||||
| 4 | 1,3 | 2 | 2 |
|
||||
| 5 | 1,2,3,4 | 4 | 1.25 |
|
||||
| 6 | 1,5 | 2 | 3 |
|
||||
| 7 | 1,2,3,4,5,6 | 6 | 1.1666... |
|
||||
| 8 | 1,3,5,7 | 4 | 2 |
|
||||
| 9 | 1,2,4,5,7,8 | 6 | 1.5 |
|
||||
| 10 | 1,3,7,9 | 4 | 2.5 |
|
||||
|
||||
</div>
|
||||
|
||||
It can be seen that `n`=6 produces a maximum `n`/φ(`n`) for `n` ≤ 10.
|
||||
|
||||
Find the value of `n` ≤ 1,000,000 for which n/φ(`n`) is a maximum.
|
||||
|
||||
# --hints--
|
||||
|
||||
`totientMaximum()` should return a number.
|
||||
|
||||
```js
|
||||
assert(typeof totientMaximum() === 'number');
|
||||
```
|
||||
|
||||
`totientMaximum()` should return 510510.
|
||||
|
||||
```js
|
||||
assert.strictEqual(totientMaximum(), 510510);
|
||||
```
|
||||
|
||||
# --seed--
|
||||
|
||||
## --seed-contents--
|
||||
|
||||
```js
|
||||
function totientMaximum() {
|
||||
|
||||
return true;
|
||||
}
|
||||
|
||||
totientMaximum();
|
||||
```
|
||||
|
||||
# --solutions--
|
||||
|
||||
```js
|
||||
// solution required
|
||||
```
|
Reference in New Issue
Block a user