Added new bonfire "No repeats please"

This commit is contained in:
Nathan Leniz
2015-03-01 08:58:05 +09:00
parent 43f9a9c30b
commit ea9691de1c

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@@ -644,5 +644,24 @@
"assert.deepEqual(inventory([], [[2, 'Hair Pin'], [3, 'Half-Eaten Apple'], [67, 'Bowling Ball'], [7, 'Toothpaste']]), [[67, 'Bowling Ball'], [2, 'Hair Pin'], [3, 'Half-Eaten Apple'], [7, 'Toothpaste']]);",
"assert.deepEqual(inventory([[0, 'Bowling Ball'], [0, 'Dirty Sock'], [0, 'Hair Pin'], [0, 'Microphone']], [[1, 'Hair Pin'], [1, 'Half-Eaten Apple'], [1, 'Bowling Ball'], [1, 'Toothpaste']]), [[1, 'Bowling Ball'], [0, 'Dirty Sock'], [1, 'Hair Pin'], [1, 'Half-Eaten Apple'], [0, 'Microphone'], [1, 'Toothpaste']]);"
]
},
{
"_id": "a7bf700cd123b9a54eef01d5",
"name": "No repeats please",
"difficulty": "4.04",
"description": [
"Return the number of total permutations of the provided string that don't have repeated consecutive letters.",
"For example, 'aab' should return 2 because it has 6 total permutations, but only 2 of them don't have the same letter (in this case 'a') repeating."
],
"challengeSeed": "function permAlone(str) {\n return str;\n}\n\npermAlone('aab');",
"tests": [
"expect(permAlone('aab')).to.be.a.number;",
"expect(permAlone('aab')).to.equal(2);",
"expect(permAlone('aaa')).to.equal(0);",
"expect(permAlone('aabb')).to.equal(8);",
"expect(permAlone('abcdefa')).to.equal(3600);",
"expect(permAlone('abfdefa')).to.equal(2640);",
"expect(permAlone('zzzzzzzz')).to.equal(0);"
]
}
]