Added new bonfire "No repeats please"
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@@ -644,5 +644,24 @@
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"assert.deepEqual(inventory([], [[2, 'Hair Pin'], [3, 'Half-Eaten Apple'], [67, 'Bowling Ball'], [7, 'Toothpaste']]), [[67, 'Bowling Ball'], [2, 'Hair Pin'], [3, 'Half-Eaten Apple'], [7, 'Toothpaste']]);",
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"assert.deepEqual(inventory([[0, 'Bowling Ball'], [0, 'Dirty Sock'], [0, 'Hair Pin'], [0, 'Microphone']], [[1, 'Hair Pin'], [1, 'Half-Eaten Apple'], [1, 'Bowling Ball'], [1, 'Toothpaste']]), [[1, 'Bowling Ball'], [0, 'Dirty Sock'], [1, 'Hair Pin'], [1, 'Half-Eaten Apple'], [0, 'Microphone'], [1, 'Toothpaste']]);"
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]
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},
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{
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"_id": "a7bf700cd123b9a54eef01d5",
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"name": "No repeats please",
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"difficulty": "4.04",
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"description": [
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"Return the number of total permutations of the provided string that don't have repeated consecutive letters.",
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"For example, 'aab' should return 2 because it has 6 total permutations, but only 2 of them don't have the same letter (in this case 'a') repeating."
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],
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"challengeSeed": "function permAlone(str) {\n return str;\n}\n\npermAlone('aab');",
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"tests": [
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"expect(permAlone('aab')).to.be.a.number;",
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"expect(permAlone('aab')).to.equal(2);",
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"expect(permAlone('aaa')).to.equal(0);",
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"expect(permAlone('aabb')).to.equal(8);",
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"expect(permAlone('abcdefa')).to.equal(3600);",
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"expect(permAlone('abfdefa')).to.equal(2640);",
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"expect(permAlone('zzzzzzzz')).to.equal(0);"
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]
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}
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]
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