feat(curriculum): restore seed + solution to Chinese (#40683)

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/emirp-primes.md

@@ -3,6 +3,7 @@ id: 599d0ba974141b0f508b37d5
 title: Emirp奖金
 challengeType: 5
 videoUrl: ''
+dashedName: emirp-primes
 ---
 
 # --description--
@@ -74,5 +75,51 @@ assert.deepEqual(emirps([7700, 8000], true), [
 assert.deepEqual(emirps([7700, 8000], false), 11);
 ```
 
+# --seed--
+
+## --seed-contents--
+
+```js
+function emirps(n) {
+
+}
+```
+
 # --solutions--
 
+```js
+function emirps(num, showEmirps)
+{
+  const is_prime = function(n)
+    {
+    if (!(n % 2) || !(n % 3)) return false;
+    let p = 1;
+    while (p * p < n)
+                    { if (n % (p += 4) == 0 || n % (p += 2) == 0)
+                            { return false; } }
+    return true;
+  };
+  const is_emirp = function(n) {
+    const r = parseInt(n.toString().split('').reverse().join(''));
+    return r != n && is_prime(n) && is_prime(r);
+  };
+
+  let i,
+    arr = [];
+  if (typeof num === 'number') {
+    for (i = 0; arr.length < num; i++) if (is_emirp(i)) arr.push(i);
+    // first x emirps
+    if (showEmirps) return arr;
+    // xth emirp
+    return arr.pop();
+  }
+
+  if (Array.isArray(num)) {
+    for (i = num[0]; i <= num[1]; i++) if (is_emirp(i)) arr.push(i);
+    // emirps between x .. y
+    if (showEmirps) return arr;
+    // number of emirps between x .. y
+    return arr.length;
+  }
+}
+```