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feat(curriculum): restore seed + solution to Chinese (#40683)

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* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
This commit is contained in:
Oliver Eyton-Williams
2021-01-13 03:31:00 +01:00
committed by GitHub
parent 0095583028
commit ee1e8abd87
4163 changed files with 57505 additions and 10540 deletions
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35
curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/factors-of-an-integer.md
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@ -3,11 +3,12 @@ id: 597f1e7fbc206f0e9ba95dc4
title: 整数因子
challengeType: 5
videoUrl: ''
dashedName: factors-of-an-integer
---
# --description--
<p>编写一个返回正整数因子的函数。 </p><p>这些因子是正整数，通过该正整数可以将被分解的数量除以产生正整数结果。 </p> ///
<p>编写一个返回正整数因子的函数。 </p><p>这些因子是正整数，通过该正整数可以将被分解的数量除以产生正整数结果。 </p> ///
# --hints--
@ -35,5 +36,37 @@ assert.deepEqual(factors(53), ans[1]);
assert.deepEqual(factors(64), ans[2]);
```
# --seed--
## --after-user-code--
```js
const ans=[[1,3,5,9,15,45],[1,53],[1,2,4,8,16,32,64]];
```
## --seed-contents--
```js
function factors(num) {
}
```
# --solutions--
```js
function factors(num)
{
let n_factors = [], i, sqr=Math.floor(Math.sqrt(num));
for (i = 1; i <=sqr ; i += 1)
if (num % i === 0)
{
n_factors.push(i);
if (num / i !== i)
n_factors.push(num / i);
}
n_factors.sort(function(a, b){return a - b;});
return n_factors;
}
```