feat(curriculum): restore seed + solution to Chinese (#40683)

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/zig-zag-matrix.md

@@ -3,6 +3,7 @@ id: 594810f028c0303b75339ad8
 title: 之字形矩阵
 challengeType: 5
 videoUrl: ''
+dashedName: zig-zag-matrix
 ---
 
 # --description--
@@ -17,7 +18,7 @@ videoUrl: ''
 10 18 19 23 24
 ```
 
-</pre>编写一个采用Z字形矩阵大小的函数，并将相应的矩阵作为二维数组返回。 
+编写一个采用Z字形矩阵大小的函数，并将相应的矩阵作为二维数组返回。
 
 # --hints--
 
@@ -57,5 +58,56 @@ ZigZagMatrix（5）必须返回指定的矩阵
 assert.deepEqual(ZigZagMatrix(5), zm5);
 ```
 
+# --seed--
+
+## --after-user-code--
+
+```js
+const zm1 = [[0]];
+const zm2 = [[0, 1], [2, 3]];
+const zm5 = [
+  [0, 1, 5, 6, 14],
+  [2, 4, 7, 13, 15],
+  [3, 8, 12, 16, 21],
+  [9, 11, 17, 20, 22],
+  [10, 18, 19, 23, 24]
+];
+```
+
+## --seed-contents--
+
+```js
+function ZigZagMatrix(n) {
+
+  return [[], []];
+}
+```
+
 # --solutions--
 
+```js
+function ZigZagMatrix(n) {
+  const mtx = [];
+  for (let i = 0; i < n; i++) {
+    mtx[i] = [];
+  }
+
+  let i = 1;
+  let j = 1;
+  for (let e = 0; e < n * n; e++) {
+    mtx[i - 1][j - 1] = e;
+    if ((i + j) % 2 === 0) {
+      // Even stripes
+      if (j < n) j++;
+      else i += 2;
+      if (i > 1) i--;
+    } else {
+      // Odd stripes
+      if (i < n) i++;
+      else j += 2;
+      if (j > 1) j--;
+    }
+  }
+  return mtx;
+}
+```