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curriculum/challenges/italian/10-coding-interview-prep/project-euler/problem-126-cuboid-layers.md

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+---
+id: 5900f3ea1000cf542c50fefd
+title: 'Problem 126: Cuboid layers'
+challengeType: 5
+forumTopicId: 301753
+dashedName: problem-126-cuboid-layers
+---
+
+# --description--
+
+The minimum number of cubes to cover every visible face on a cuboid measuring 3 x 2 x 1 is twenty-two.
+
+If we then add a second layer to this solid it would require forty-six cubes to cover every visible face, the third layer would require seventy-eight cubes, and the fourth layer would require one-hundred and eighteen cubes to cover every visible face. However, the first layer on a cuboid measuring 5 x 1 x 1 also requires twenty-two cubes; similarly the first layer on cuboids measuring 5 x 3 x 1, 7 x 2 x 1, and 11 x 1 x 1 all contain forty-six cubes. We shall define C(n) to represent the number of cuboids that contain n cubes in one of its layers. So C(22) = 2, C(46) = 4, C(78) = 5, and C(118) = 8. It turns out that 154 is the least value of n for which C(n) = 10. Find the least value of n for which C(n) = 1000.
+
+# --hints--
+
+`euler126()` should return 18522.
+
+```js
+assert.strictEqual(euler126(), 18522);
+```
+
+# --seed--
+
+## --seed-contents--
+
+```js
+function euler126() {
+
+  return true;
+}
+
+euler126();
+```
+
+# --solutions--
+
+```js
+// solution required
+```