feat: enable new langs (#42491)

Enable italian and portuguese
This commit is contained in:
Nicholas Carrigan (he/him)
2021-06-15 00:49:18 -07:00
committed by GitHub
parent d8d6d20793
commit f25e3e69f8
3301 changed files with 423168 additions and 6 deletions

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---
id: 594db4d0dedb4c06a2a4cefd
title: Babbage problem
challengeType: 5
forumTopicId: 302229
dashedName: babbage-problem
---
# --description--
[Charles Babbage](https://en.wikipedia.org/wiki/Charles_Babbage "wp: Charles_Babbage"), looking ahead to the sorts of problems his Analytical Engine would be able to solve, gave this example:
<blockquote>
What is the smallest positive integer whose square ends in the digits 269,696?
<footer style='margin-left: 2em;'>Babbage, letter to Lord Bowden, 1837; see Hollingdale and Tootill, <i>Electronic Computers</i>, second edition, 1970, p. 125.</footer>
</blockquote>
He thought the answer might be 99,736, whose square is 9,947,269,696; but he couldn't be certain.
The task is to find out if Babbage had the right answer.
# --instructions--
Implement a function to return the lowest integer that satisfies the Babbage problem. If Babbage was right, return Babbage's number.
# --hints--
`babbage` should be a function.
```js
assert(typeof babbage === 'function');
```
`babbage(99736, 269696)` should not return 99736 (there is a smaller answer).
```js
assert.equal(babbage(babbageAns, endDigits), answer);
```
# --seed--
## --after-user-code--
```js
const babbageAns = 99736;
const endDigits = 269696;
const answer = 25264;
```
## --seed-contents--
```js
function babbage(babbageNum, endDigits) {
return true;
}
```
# --solutions--
```js
function babbage(babbageAns, endDigits) {
const babbageNum = Math.pow(babbageAns, 2);
const babbageStartDigits = parseInt(babbageNum.toString().replace('269696', ''));
let answer = 99736;
// count down from this answer and save any sqrt int result. return lowest one
for (let i = babbageStartDigits; i >= 0; i--) {
const num = parseInt(i.toString().concat('269696'));
const result = Math.sqrt(num);
if (result === Math.floor(Math.sqrt(num))) {
answer = result;
}
}
return answer;
}
```