From f5a905b7c228c6f6188b37fb5e6e036b79afdbf7 Mon Sep 17 00:00:00 2001
From: gikf <60067306+gikf@users.noreply.github.com>
Date: Sat, 20 Feb 2021 07:34:38 +0100
Subject: [PATCH] fix(learn): unmangle challenge description (#41182)

---
 .../10-coding-interview-prep/rosetta-code/sum-of-a-series.md    | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/curriculum/challenges/english/10-coding-interview-prep/rosetta-code/sum-of-a-series.md b/curriculum/challenges/english/10-coding-interview-prep/rosetta-code/sum-of-a-series.md
index 69fdff5699..3e7e0b4e4f 100644
--- a/curriculum/challenges/english/10-coding-interview-prep/rosetta-code/sum-of-a-series.md
+++ b/curriculum/challenges/english/10-coding-interview-prep/rosetta-code/sum-of-a-series.md
@@ -8,7 +8,7 @@ dashedName: sum-of-a-series
 
 # --description--
 
-Compute the **n**<sup>th</sup> term of a [series](<https://en.wikipedia.org/wiki/Series (mathematics)>), i.e. the sum of the **n** first terms of the corresponding [sequence](https://en.wikipedia.org/wiki/sequence). Informally this value, or its limit when **n** tends to infinity, is also called the *sum of the series*, thus the title of this task. For this task, use: $S*n = \\sum*{k=1}^n \\frac{1}{k^2}$ and compute $S\_{1000}$ This approximates the [zeta function](<https://en.wikipedia.org/wiki/Riemann zeta function>) for S=2, whose exact value $\\zeta(2) = {\\pi^2\\over 6}$ is the solution of the [Basel problem](<https://en.wikipedia.org/wiki/Basel problem>).
+Compute the **n**<sup>th</sup> term of a [series](<https://en.wikipedia.org/wiki/Series (mathematics)>), i.e. the sum of the **n** first terms of the corresponding [sequence](https://en.wikipedia.org/wiki/sequence). Informally this value, or its limit when **n** tends to infinity, is also called the *sum of the series*, thus the title of this task. For this task, use: $S_n = \displaystyle\sum_{k=1}^n \frac{1}{k^2}$.
 
 # --instructions--