Use the Spread Operator to Evaluate Arrays In-Place, adding the proper solution. (Fixes #35022) (#35037)

* Adding proper solution for spread operation

Use the Spread Operator to Evaluate Arrays In-Place: adding the proper solution for the challenge

* made some more changes

* Fixed the Solution in es6 class constructor guide

Fixed the vegetable solution in Guide: Use class Syntax to Define a Constructor Function

guide/english/certifications/javascript-algorithms-and-data-structures/es6/use-class-syntax-to-define-a-constructor-function/index.md

@@ -19,22 +19,6 @@ Put a constructor with a parameter called `name`, and set it to `this.name`.
 
 ## Solution:
 
-```javascript
-function makeClass() {
-  "use strict";
-  /* Alter code below this line */
-  class Vegetable {
-    constructor(name){
-      this.name = name;
-    }
-  }
-  /* Alter code above this line */
-  return Vegetable;
-}
-```
-
-=======
-
 Spoiler Warning: here is a basic solution to this challenge in case you're stuck.
 
 ```javascript
@@ -43,8 +27,8 @@ function makeClass() {
   /* Alter code below this line */
 
    class Vegetable {
-     constructor(Vegetable){
+     constructor(name){
-       this.Vegetable = Vegetable;
+       this.name = name;
   
      }
    }

guide/english/certifications/javascript-algorithms-and-data-structures/es6/use-the-spread-operator-to-evaluate-arrays-in-place/index.md

@@ -35,5 +35,18 @@ let numbers = [-12, 160, 0, -3, 51];
 let minNum = Math.min(...numbers);
 console.log(minNum);//-12
 ```
+# SPOILER WARNING: SOLUTION AHEAD
+### The Solution
 
+> Unpacking the arr1 using the spread operator and then copying those values to arr2
+
+```javascript
+const arr1 = ['JAN', 'FEB', 'MAR', 'APR', 'MAY'];
+let arr2;
+(function() {
+  "use strict";
+  arr2 = [...arr1]; // change this line
+})();
+console.log(arr2);
+```
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