Compute all three of the Pythagorean means of the set of integers 1 through 10 (inclusive).
Show that $A(x_1,\ldots,x_n) \geq G(x_1,\ldots,x_n) \geq H(x_1,\ldots,x_n)$ for this set of positive integers.
The most common of the three means, the arithmetic mean, is the sum of the list divided by its length: $ A(x_1, \ldots, x_n) = \frac{x_1 + \cdots + x_n}{n}$The geometric mean is the $n$th root of the product of the list: $ G(x_1, \ldots, x_n) = \sqrt[n]{x_1 \cdots x_n} $The harmonic mean is $n$ divided by the sum of the reciprocal of each item in the list: $ H(x_1, \ldots, x_n) = \frac{n}{\frac{1}{x_1} + \cdots + \frac{1}{x_n}} $Assume the input is an ordered array of all inclusive numbers.
For the answer, please output an object in the following format:
{
values: {
Arithmetic: 5.5,
Geometric: 4.528728688116765,
Harmonic: 3.414171521474055
},
test: 'is A >= G >= H ? yes'
}
pythagoreanMeans is a function.
testString: assert(typeof pythagoreanMeans === 'function', 'pythagoreanMeans is a function.');
- text: pythagoreanMeans([1, 2, ..., 10]) should equal the same output above.
testString: assert.deepEqual(pythagoreanMeans(range1), answer1, 'pythagoreanMeans([1, 2, ..., 10]) should equal the same output above.');
```