---
id: 56533eb9ac21ba0edf2244df
challengeType: 1
videoUrl: 'https://scrimba.com/c/cdBKWCV'
forumTopicId: 18242
localeTitle: 在 Switch 语句添加多个相同选项
---
## Description
如果你忘了给switch的每一条case添加break，那么直到遇见break为止，后续的case会一直执行。如果你想为多个不同的输入设置相同的结果，可以这样写：
```js
switch(val) {
case 1:
case 2:
case 3:
result = "1, 2, or 3";
break;
case 4:
result = "4 alone";
}
```
这样，1、2、3 都会有相同的结果。
## Instructions
请写一个switch语句，根据输入的val的范围得出对应的answer：
1-3 - "Low"
4-6 - "Mid"
7-9 - "High"
提示：
你的case应基于范围中的每一个数字编写。
## Tests
```yml
tests:
- text: sequentialSizes(1)应该返回 "Low"。
testString: assert(sequentialSizes(1) === "Low");
- text: sequentialSizes(2)应该返回 "Low"。
testString: assert(sequentialSizes(2) === "Low");
- text: sequentialSizes(3)应该返回 "Low"。
testString: assert(sequentialSizes(3) === "Low");
- text: sequentialSizes(4)应该返回 "Mid"。
testString: assert(sequentialSizes(4) === "Mid");
- text: sequentialSizes(5)应该返回 "Mid"。
testString: assert(sequentialSizes(5) === "Mid");
- text: sequentialSizes(6)应该返回 "Mid"。
testString: assert(sequentialSizes(6) === "Mid");
- text: sequentialSizes(7)应该返回 "High"。
testString: assert(sequentialSizes(7) === "High");
- text: sequentialSizes(8)应该返回 "High"。
testString: assert(sequentialSizes(8) === "High");
- text: sequentialSizes(9)应该返回 "High"。
testString: assert(sequentialSizes(9) === "High");
- text: 你不应使用if或else语句。
testString: assert(!/else/g.test(code) || !/if/g.test(code));
- text: 你应该编写 9 个case语句。
testString: assert(code.match(/case/g).length === 9);
```
## Challenge Seed
```js
function sequentialSizes(val) {
var answer = "";
// Only change code below this line
// Only change code above this line
return answer;
}
// Change this value to test
sequentialSizes(1);
```
## Solution
```js
function sequentialSizes(val) {
var answer = "";
switch(val) {
case 1:
case 2:
case 3:
answer = "Low";
break;
case 4:
case 5:
case 6:
answer = "Mid";
break;
case 7:
case 8:
case 9:
answer = "High";
}
return answer;
}
```