--- id: a7bf700cd123b9a54eef01d5 title: 请不要重复 challengeType: 5 videoUrl: '' dashedName: no-repeats-please --- # --description-- 返回没有重复连续字母的提供字符串的总排列数。假设提供的字符串中的所有字符都是唯一的。例如, `aab`应该返回2,因为它总共有6个排列( `aab` , `aab` , `aba` , `aba` , `baa` , `baa` ),但只有2个( `aba`和`aba` )没有相同的字母(在这种情况下为`a` )重复。如果卡住,请记得使用[Read-Search-Ask](https://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck-coding/19514) 。尝试配对程序。编写自己的代码。 # --hints-- `permAlone("aab")`应返回一个数字。 ```js assert.isNumber(permAlone('aab')); ``` `permAlone("aab")`应返回2。 ```js assert.strictEqual(permAlone('aab'), 2); ``` `permAlone("aaa")`应该返回0。 ```js assert.strictEqual(permAlone('aaa'), 0); ``` `permAlone("aabb")`应该返回8。 ```js assert.strictEqual(permAlone('aabb'), 8); ``` `permAlone("abcdefa")`应返回3600。 ```js assert.strictEqual(permAlone('abcdefa'), 3600); ``` `permAlone("abfdefa")`应返回2640。 ```js assert.strictEqual(permAlone('abfdefa'), 2640); ``` `permAlone("zzzzzzzz")`应该返回0。 ```js assert.strictEqual(permAlone('zzzzzzzz'), 0); ``` `permAlone("a")`应返回1。 ```js assert.strictEqual(permAlone('a'), 1); ``` `permAlone("aaab")`应该返回0。 ```js assert.strictEqual(permAlone('aaab'), 0); ``` `permAlone("aaabb")`应该返回12。 ```js assert.strictEqual(permAlone('aaabb'), 12); ``` # --seed-- ## --seed-contents-- ```js function permAlone(str) { return str; } permAlone('aab'); ``` # --solutions-- ```js function permAlone(str) { return permuter(str).filter(function(perm) { return !perm.match(/(.)\1/g); }).length; } function permuter(str) { // http://staff.roguecc.edu/JMiller/JavaScript/permute.html //permArr: Global array which holds the list of permutations //usedChars: Global utility array which holds a list of "currently-in-use" characters var permArr = [], usedChars = []; function permute(input) { //convert input into a char array (one element for each character) var i, ch, chars = input.split(""); for (i = 0; i < chars.length; i++) { //get and remove character at index "i" from char array ch = chars.splice(i, 1); //add removed character to the end of used characters usedChars.push(ch); //when there are no more characters left in char array to add, add used chars to list of permutations if (chars.length === 0) permArr[permArr.length] = usedChars.join(""); //send characters (minus the removed one from above) from char array to be permuted permute(chars.join("")); //add removed character back into char array in original position chars.splice(i, 0, ch); //remove the last character used off the end of used characters array usedChars.pop(); } } permute(str); return permArr; } permAlone('aab'); ```