--- id: 5992e222d397f00d21122931 title: 斐波那契字 challengeType: 5 videoUrl: '' dashedName: fibonacci-word --- # --description--

编写一个函数将Fibonacci字返回到N.N将作为参数提供给函数。该函数应返回一个对象数组。对象的形式应为:{N:1,长度:1,熵:0,单词:'1'}。更多细节如下:

Fibonacci Word可以类似于Fibonacci Sequence的方式创建, 如下所述

将F_Word 1定义为1

将F_Word 2定义为0

将F_Word 3表示为F_Word 2与F_Word 1连接,即:01

将F_Word n表示为F_Word n-1与F_word n-2连接

# --hints-- `fibWord`是一个功能。 ```js assert(typeof fibWord === 'function'); ``` `fibWord(5)`应该返回一个数组。 ```js assert(Array.isArray(fibWord(5))); ``` `fibWord(5)`应该返回`'+JSON.stringify(ans)+'` 。 ```js assert.deepEqual(fibWord(5), ans); ``` # --seed-- ## --after-user-code-- ```js let ans=[ { N: 1, Length: 1, Entropy: 0, Word: '1' }, { N: 2, Length: 1, Entropy: 0, Word: '0' }, { N: 3, Length: 2, Entropy: 1, Word: '01' }, { N: 4, Length: 3, Entropy: 0.9182958340544896, Word: '010' }, { N: 5, Length: 5, Entropy: 0.9709505944546688, Word: '01001' }]; ``` ## --seed-contents-- ```js function fibWord(n) { } ``` # --solutions-- ```js function fibWord(n) { function entropy(s) { //create an object containing each individual char //and the amount of iterations per char function prob(s) { var h = Object.create(null); s.split('').forEach(function(c) { h[c] && h[c]++ || (h[c] = 1); }); return h; } s = s.toString(); //just in case var e = 0, l = s.length, h = prob(s); for (var i in h ) { var p = h[i]/l; e -= p * Math.log(p) / Math.log(2); } return e; } var wOne = "1", wTwo = "0", wNth = [wOne, wTwo], w = "", o = []; for (var i = 0; i < n; i++) { if (i === 0 || i === 1) { w = wNth[i]; } else { w = wNth[i - 1] + wNth[i - 2]; wNth.push(w); } var l = w.length; var e = entropy(w); if (l <= 21) { o.push({ N: i + 1, Length: l, Entropy: e, Word: w }); } else { o.push({ N: i + 1, Length: l, Entropy: e, Word: "..." }); } } return o; } ```