aab
should return 2 because it has 6 total permutations (aab
, aab
, aba
, aba
, baa
, baa
), but only 2 of them (aba
and aba
) don't have the same letter (in this case a
) repeating.
Remember to use Read-Search-Ask if you get stuck. Try to pair program. Write your own code.
permAlone("aab")
should return a number.
testString: 'assert.isNumber(permAlone(''aab''), ''permAlone("aab")
should return a number.'');'
- text: permAlone("aab")
should return 2.
testString: 'assert.strictEqual(permAlone(''aab''), 2, ''permAlone("aab")
should return 2.'');'
- text: permAlone("aaa")
should return 0.
testString: 'assert.strictEqual(permAlone(''aaa''), 0, ''permAlone("aaa")
should return 0.'');'
- text: permAlone("aabb")
should return 8.
testString: 'assert.strictEqual(permAlone(''aabb''), 8, ''permAlone("aabb")
should return 8.'');'
- text: permAlone("abcdefa")
should return 3600.
testString: 'assert.strictEqual(permAlone(''abcdefa''), 3600, ''permAlone("abcdefa")
should return 3600.'');'
- text: permAlone("abfdefa")
should return 2640.
testString: 'assert.strictEqual(permAlone(''abfdefa''), 2640, ''permAlone("abfdefa")
should return 2640.'');'
- text: permAlone("zzzzzzzz")
should return 0.
testString: 'assert.strictEqual(permAlone(''zzzzzzzz''), 0, ''permAlone("zzzzzzzz")
should return 0.'');'
- text: permAlone("a")
should return 1.
testString: 'assert.strictEqual(permAlone(''a''), 1, ''permAlone("a")
should return 1.'');'
- text: permAlone("aaab")
should return 0.
testString: 'assert.strictEqual(permAlone(''aaab''), 0, ''permAlone("aaab")
should return 0.'');'
- text: permAlone("aaabb")
should return 12.
testString: 'assert.strictEqual(permAlone(''aaabb''), 12, ''permAlone("aaabb")
should return 12.'');'
```