--- title: Sum to 100 --- # Sum to 100 --- ## Solutions
Solution 1 (Click to Show/Hide) ```javascript function sumTo100(n) { var permutationsWithRepetition = function(n, as) { return as.length > 0 ? foldl1(curry(cartesianProduct)(as), replicate(n, as)) : []; }; var cartesianProduct = function(xs, ys) { return [].concat.apply([], xs.map(function(x) { return [].concat.apply([], ys.map(function(y) { return [ [x].concat(y) ]; })); })); }; var curry = function(f) { return function(a) { return function(b) { return f(a, b); }; }; }; var flip = function(f) { return function(a, b) { return f.apply(null, [b, a]); }; }; var foldl1 = function(f, xs) { return xs.length > 0 ? xs.slice(1) .reduce(f, xs[0]) : []; }; var replicate = function(n, a) { var v = [a], o = []; if (n < 1) return o; while (n > 1) { if (n & 1) o = o.concat(v); n >>= 1; v = v.concat(v); } return o.concat(v); }; var asSum = function(xs) { var dct = xs.reduceRight(function(a, sign, i) { var d = i + 1; // zero-based index to [1-9] positions if (sign !== 0) { // Sum increased, digits cleared return { digits: [], n: a.n + sign * parseInt([d].concat(a.digits) .join(''), 10) }; } else return { // Digits extended, sum unchanged digits: [d].concat(a.digits), n: a.n }; }, { digits: [], n: 0 }); return dct.n + ( dct.digits.length > 0 ? parseInt(dct.digits.join(''), 10) : 0 ); }; var asString = function(xs) { var ns = xs.reduce(function(a, sign, i) { var d = (i + 1) .toString(); return sign === 0 ? a + d : a + (sign > 0 ? '+' : '-') + d; }, ''); return ns[0] === '+' ? tail(ns) : ns; }; var universe = permutationsWithRepetition(9, [0, 1, -1]) .filter(function(x) { return x[0] !== 1 && asSum(x) === n; }).map(asString); return universe.sort() } ```