--- id: 587d8254367417b2b2512c6e title: Perform a Difference on Two Sets of Data challengeType: 1 forumTopicId: 301706 --- ## Description
In this exercise we are going to perform a difference on 2 sets of data. We will create a method on our Set data structure called difference. A difference of sets should compare two sets and return the items present in the first set that are absent in the second. This method should take another Set as an argument and return the difference of the two sets. For example, if setA = ['a','b','c'] and setB = ['a','b','d','e'], then the difference of setA and setB is: setA.difference(setB) = ['c'].
## Instructions
## Tests
```yml tests: - text: Your Set class should have a difference method. testString: assert((function(){var test = new Set(); return (typeof test.difference === 'function')})()); - text: Your difference method should return the proper collection. testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('c'); setB.add('d'); var differenceSetAB = setA.difference(setB); return (differenceSetAB.size() === 2) && DeepEqual(differenceSetAB.values(), [ 'a', 'b' ])})()); ```
## Challenge Seed
```js class Set { constructor() { // This will hold the set this.dictionary = {}; this.length = 0; } // This method will check for the presence of an element and return true or false has(element) { return this.dictionary[element] !== undefined; } // This method will return all the values in the set values() { return Object.keys(this.dictionary); } // This method will add an element to the set add(element) { if (!this.has(element)) { this.dictionary[element] = true; this.length++; return true; } return false; } // This method will remove an element from a set remove(element) { if (this.has(element)) { delete this.dictionary[element]; this.length--; return true; } return false; } // This method will return the size of the set size() { return this.length; } // This is our union method union(set) { const newSet = new Set(); this.values().forEach(value => { newSet.add(value); }) set.values().forEach(value => { newSet.add(value); }) return newSet; } // This is our intersection method intersection(set) { const newSet = new Set(); let largeSet; let smallSet; if (this.dictionary.length > set.length) { largeSet = this; smallSet = set; } else { largeSet = set; smallSet = this; } smallSet.values().forEach(value => { if (largeSet.dictionary[value]) { newSet.add(value); } }) return newSet; } // Only change code below this line // Only change code above this line } ```
## Solution
```js class Set { constructor() { this.dictionary = {}; this.length = 0; } has(element) { return this.dictionary[element] !== undefined; } values() { return Object.keys(this.dictionary); } add(element) { if (!this.has(element)) { this.dictionary[element] = true; this.length++; return true; } return false; } remove(element) { if (this.has(element)) { delete this.dictionary[element]; this.length--; return true; } return false; } size() { return this.length; } union(set) { const newSet = new Set(); this.values().forEach(value => { newSet.add(value); }) set.values().forEach(value => { newSet.add(value); }) return newSet; } intersection(set) { const newSet = new Set(); let largeSet; let smallSet; if (this.dictionary.length > set.length) { largeSet = this; smallSet = set; } else { largeSet = set; smallSet = this; } smallSet.values().forEach(value => { if (largeSet.dictionary[value]) { newSet.add(value); } }) return newSet; } difference(set) { const newSet = new Set(); this.values().forEach(value => { if (!set.dictionary[value]) { newSet.add(value); } }) return newSet; } } ```