--- id: 5a24c314108439a4d403615a challengeType: 6 forumTopicId: 301447 title: 从数组中删除项目 --- ## Description
是时候练习从数组中删除项目了。扩展运算符也可以在这里使用。其他有用的JavaScript方法包括slice()concat()
## Instructions
reducer 和 action creator 被修改为根据项目的索引从数组中删除一个项目。完成编写 reducer 以便返回一个新的状态数组,并删除特定索引处的项目。
## Tests
```yml tests: - text: Redux store 应该存在并初始化一个[0,1,2,3,4,5]的状态。 testString: assert((function() { const initialState = store.getState(); return (Array.isArray(initialState) === true && DeepEqual(initialState, [0, 1, 2, 3, 4, 5])); })()); - text: removeItemimmutableReducer都应该是一个函数。 testString: assert(typeof removeItem === 'function' && typeof immutableReducer === 'function'); - text: dispatch removeItem action creator 应该从 state 中删除项目,不应该改变 state。 testString: assert((function() { const initialState = store.getState(); const isFrozen = DeepFreeze(initialState); store.dispatch(removeItem(3)); const state_1 = store.getState(); store.dispatch(removeItem(2)); const state_2 = store.getState(); store.dispatch(removeItem(0)); store.dispatch(removeItem(0)); store.dispatch(removeItem(0)); const state_3 = store.getState(); return isFrozen && DeepEqual(state_1, [0, 1, 2, 4, 5]) && DeepEqual(state_2, [0, 1, 4, 5]) && DeepEqual(state_3, [5]); })()); ```
## Challenge Seed
```jsx const immutableReducer = (state = [0,1,2,3,4,5], action) => { switch(action.type) { case 'REMOVE_ITEM': // 不要在这里改变 state 否则测试会失败。 return default: return state; } }; const removeItem = (index) => { return { type: 'REMOVE_ITEM', index } } const store = Redux.createStore(immutableReducer); ```
## Solution
```js const immutableReducer = (state = [0,1,2,3,4,5], action) => { switch(action.type) { case 'REMOVE_ITEM': return [ ...state.slice(0, action.index), ...state.slice(action.index + 1) ]; default: return state; } }; const removeItem = (index) => { return { type: 'REMOVE_ITEM', index } } const store = Redux.createStore(immutableReducer); ```