---
id: 56104e9e514f539506016a5c
title: Iterate Odd Numbers With a For Loop
challengeType: 1
---
## Description
For loops don't have to iterate one at a time. By changing our final-expression, we can count by even numbers.
We'll start at i = 0 and loop while i < 10. We'll increment i by 2 each loop with i += 2.
var ourArray = [];
for (var i = 0; i < 10; i += 2) {
ourArray.push(i);
}
ourArray will now contain [0,2,4,6,8].
Let's change our initialization so we can count by odd numbers.
## Instructions
Push the odd numbers from 1 through 9 to myArray using a for loop.
## Tests
```yml
- text: You should be using a for loop for this.
testString: 'assert(code.match(/for\s*\(/g).length > 1, ''You should be using a for loop for this.'');'
- text: 'myArray should equal [1,3,5,7,9].'
testString: 'assert.deepEqual(myArray, [1,3,5,7,9], ''myArray should equal [1,3,5,7,9].'');'
```
## Challenge Seed
```js
// Example
var ourArray = [];
for (var i = 0; i < 10; i += 2) {
ourArray.push(i);
}
// Setup
var myArray = [];
// Only change code below this line.
```
### After Test
```js
console.info('after the test');
```
## Solution
```js
var ourArray = [];
for (var i = 0; i < 10; i += 2) {
ourArray.push(i);
}
var myArray = [];
for (var i = 1; i < 10; i += 2) {
myArray.push(i);
}
```