prototype
object from a supertype
constructor function can still have its own methods in addition to inherited methods.
For example, Bird
is a constructor that inherits its prototype
from Animal
:
```js
function Animal() { }
Animal.prototype.eat = function() {
console.log("nom nom nom");
};
function Bird() { }
Bird.prototype = Object.create(Animal.prototype);
Bird.prototype.constructor = Bird;
```
In addition to what is inherited from Animal
, you want to add behavior that is unique to Bird
objects. Here, Bird
will get a fly()
function. Functions are added to Bird's
prototype
the same way as any constructor function:
```js
Bird.prototype.fly = function() {
console.log("I'm flying!");
};
```
Now instances of Bird
will have both eat()
and fly()
methods:
```js
let duck = new Bird();
duck.eat(); // prints "nom nom nom"
duck.fly(); // prints "I'm flying!"
```
Dog
object inherits from Animal
and the Dog's
prototype
constructor is set to Dog. Then add a bark()
method to the Dog
object so that beagle
can both eat()
and bark()
. The bark()
method should print "Woof!" to the console.
Animal
should not respond to the bark()
method.
testString: assert(typeof Animal.prototype.bark == "undefined");
- text: Dog
should inherit the eat()
method from Animal
.
testString: assert(typeof Dog.prototype.eat == "function");
- text: Dog
should have the bark()
method as an own
property.
testString: assert(Dog.prototype.hasOwnProperty('bark'));
- text: beagle
should be an instanceof
Animal
.
testString: assert(beagle instanceof Animal);
- text: The constructor for beagle
should be set to Dog
.
testString: assert(beagle.constructor === Dog);
```