--- id: 5900f39c1000cf542c50feaf challengeType: 5 title: 'Problem 48: Self powers' --- ## Description
The series, 11 + 22 + 33 + ... + 1010 = 10405071317. Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.
## Instructions
## Tests
```yml tests: - text: 'selfPowers(10, 3) should return 317.' testString: 'assert.strictEqual(selfPowers(10, 3), 317, "selfPowers(10, 3) should return 317.");' - text: 'selfPowers(150, 6) should return 29045.' testString: 'assert.strictEqual(selfPowers(150, 6), 29045, "selfPowers(150, 6) should return 29045.");' - text: 'selfPowers(673, 7) should return 2473989.' testString: 'assert.strictEqual(selfPowers(673, 7), 2473989, "selfPowers(673, 7) should return 2473989.");' - text: 'selfPowers(1000, 10) should return 9110846700.' testString: 'assert.strictEqual(selfPowers(1000, 10), 9110846700, "selfPowers(1000, 10) should return 9110846700.");' ```
## Challenge Seed
```js function selfPowers(power, lastDigits) { // Good luck! return true; } selfPowers(1000, 10); ```
## Solution
```js function selfPowers(power, lastDigits) { let sum = 0; const modulo = Math.pow(10, lastDigits); for (let i = 1; i <= power; i++) { let temp = i; for (let j = 1; j < i; j++) { temp *= i; temp %= modulo; } sum += temp; sum %= modulo; } return sum; } ```