--- id: 5 localeTitle: 5900f3a11000cf542c50feb4 challengeType: 5 title: 'Problem 53: Combinatoric selections' --- ## Description
Hay exactamente diez formas de seleccionar tres de cinco, 12345: 123, 124, 125, 134, 135, 145, 234, 235, 245 y 345 En combinatoria, usamos la notación, 5C3 = 10. In general, nCr = n! r! (n − r)! , donde r ≤ n, n! = n × (n − 1) × ... × 3 × 2 × 1, y 0! = 1. No es hasta n = 23, que un valor excede de un millón: 23C10 = 1144066. ¿Cuántos, no necesariamente distintos, valores de nCr, para 1 ≤ n ≤ 100, son mayores que un millón? ?
## Instructions
## Tests
```yml tests: - text: combinatoricSelections(1000) deben devolver 4626. testString: 'assert.strictEqual(combinatoricSelections(1000), 4626, "combinatoricSelections(1000) should return 4626.");' - text: combinatoricSelections(10000) deben devolver 4431. testString: 'assert.strictEqual(combinatoricSelections(10000), 4431, "combinatoricSelections(10000) should return 4431.");' - text: combinatoricSelections(100000) deben devolver 4255. testString: 'assert.strictEqual(combinatoricSelections(100000), 4255, "combinatoricSelections(100000) should return 4255.");' - text: combinatoricSelections(1000000) deben devolver 4075. testString: 'assert.strictEqual(combinatoricSelections(1000000), 4075, "combinatoricSelections(1000000) should return 4075.");' ```
## Challenge Seed
```js function combinatoricSelections(limit) { // Good luck! return 1; } combinatoricSelections(1000000); ```
## Solution
```js function combinatoricSelections(limit) { const factorial = n => Array.apply(null, { length: n }) .map((_, i) => i + 1) .reduce((p, c) => p * c, 1); let result = 0; const nMax = 100; for (let n = 1; n <= nMax; n++) { for (let r = 0; r <= n; r++) { if (factorial(n) / (factorial(r) * factorial(n - r)) >= limit) result++; } } return result; } ```