--- title: Iterate Through All an Array's Items Using For Loops --- # Iterate Through All an Array's Items Using For Loops ### Hint 1 - A nested `for` loop must be used to search through every element in the array. ```javascript for (let i = 0; i < arr.length; i++) {} ``` ### Hint 2 - Every element of the array must then be compared to the `elem` parameter passed through the `filteredArray()` function. ```javascript if (arr[i].indexOf(elem) == -1) { } ``` ### Hint 3 - If a match is NOT found then `newArr` have that entire subarray added. The `push()` function is very useful here. ```javascript newArr.push(arr[i]); ``` - Once that entire subarray is added to `newArr` the loop continue with the next element. --- ## Solutions
Solution 1 (Click to Show/Hide) ```javascript function filteredArray(arr, elem) { let newArr = []; // change code below this line for (let i = 0; i < arr.length; i++) { if (arr[i].indexOf(elem) == -1) { //Checks every parameter for the element and if is NOT there continues the code newArr.push(arr[i]); //Inserts the element of the array in the new filtered array } } // change code above this line return newArr; } // change code here to test different cases: console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3)); ```