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freeCodeCamp/server/utils/user-stats.test.js
Berkeley Martinez 3e6e214d51 Chore(tests): Move tests
2016-09-23 15:38:49 -07:00

430 lines
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JavaScript
Raw Blame History

import test from 'tape';
import moment from 'moment-timezone';
import sinon from 'sinon';
import {
prepUniqueDays,
calcCurrentStreak,
calcLongestStreak
} from './user-stats';
// setting now to 2016-02-03T11:00:00 (PST)
const clock = sinon.useFakeTimers(1454526000000);
const PST = 'America/Los_Angeles';
test('Prepare calendar items', function(t) {
t.plan(5);
t.deepEqual(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('8/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('8/3/2015 20:00', 'M/D/YYYY H:mm').valueOf()
]),
[1438560000000],
'should return correct epoch when all entries fall into one day in UTC'
);
t.deepEqual(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
]),
[1438560000000],
'should return correct epoch when given two identical dates'
);
t.deepEqual(
prepUniqueDays([
// 8/2/2015 in America/Los_Angeles
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('8/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('8/3/2015 20:00', 'M/D/YYYY H:mm').valueOf()
], PST),
[1438498800000, 1438585200000],
'should return 2 epochs when dates fall into two days in PST'
);
t.deepEqual(
prepUniqueDays([
moment.utc('8/1/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('3/3/2015 14:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/30/2014 20:00', 'M/D/YYYY H:mm').valueOf()
]),
[1412035200000, 1425340800000, 1438387200000],
'should return 3 epochs when dates fall into three days'
);
t.deepEqual(
prepUniqueDays([
1438387200000, 1425340800000, 1412035200000
]),
[1412035200000, 1425340800000, 1438387200000],
'should return same but sorted array if all input dates are start of day'
);
});
test('Current streak calculation', function(t) {
t.plan(11);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
1,
'should return 1 day when today one challenge was completed'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'hours')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
1,
'should return 1 day when today more than one challenge was completed'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf()
])
),
0,
'should return 0 day when today 0 challenges were completed'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
2,
'should return 2 days when today and yesterday challenges were completed'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc(moment.utc().subtract(2, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
3,
'should return 3 when today and for two days before user was activity'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(47, 'hours')).valueOf(),
moment.utc(moment.utc().subtract(11, 'hours')).valueOf()
])
),
1,
'should return 1 when there is 1.5 days long break and ' +
'dates fall into two days separated by third'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(40, 'hours')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
2,
'should return 2 when the break is more than 1.5 days ' +
'but dates fall into two consecutive days'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'hours')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
1,
'should return correct count in default timezone UTC ' +
'given `undefined` timezone'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
], PST),
PST
),
2,
'should return 2 days when today and yesterday ' +
'challenges were completed given PST'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
1453174506164, 1453175436725, 1453252466853, 1453294968225,
1453383782844, 1453431903117, 1453471373080, 1453594733026,
1453645014058, 1453746762747, 1453747659197, 1453748029416,
1453818029213, 1453951796007, 1453988570615, 1454069704441,
1454203673979, 1454294055498, 1454333545125, 1454415163903,
1454519128123, moment.tz(PST).valueOf()
], PST),
PST
),
17,
'should return 17 when there is no break in given timezone ' +
'(but would be the break if in UTC)'
);
t.equal(
calcCurrentStreak(
prepUniqueDays([
1453174506164, 1453175436725, 1453252466853, 1453294968225,
1453383782844, 1453431903117, 1453471373080, 1453594733026,
1453645014058, 1453746762747, 1453747659197, 1453748029416,
1453818029213, 1453951796007, 1453988570615, 1454069704441,
1454203673979, 1454294055498, 1454333545125, 1454415163903,
1454519128123, moment.utc().valueOf()
])
),
4,
'should return 4 when there is a break in UTC ' +
'(but would be no break in PST)'
);
});
test('Longest streak calculation', function(t) {
t.plan(14);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('9/12/2015 4:00', 'M/D/YYYY H:mm').valueOf()
])
),
1,
'should return 1 when there is the only one one-day-long streak available'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 1:00', 'M/D/YYYY H:mm').valueOf()
])
),
4,
'should return 4 when there is the only one ' +
'more-than-one-days-long streak available'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
1,
'should return 1 when there is only one one-day-long streak and it is today'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
2,
'should return 2 when yesterday and today makes longest streak'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/4/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/5/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/6/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/7/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('11/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
])
),
4,
'should return 4 when there is a month long break'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 15:30', 'M/D/YYYY H:mm').valueOf(),
moment.utc(moment.utc('9/12/2015 15:30', 'M/D/YYYY H:mm')
.add(37, 'hours')).valueOf(),
moment.utc('9/14/2015 22:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/15/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/3/2015 2:00', 'M/D/YYYY H:mm').valueOf()
])
),
2,
'should return 2 when there is a more than 1.5 days ' +
'long break of (36 hours)'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc(moment.utc().subtract(2, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc().valueOf()
])
),
4,
'should return 4 when the longest streak consist of ' +
'several same day timestamps'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('8/3/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 5:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/12/2015 1:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/13/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('10/14/2015 5:00', 'M/D/YYYY H:mm').valueOf()
])
),
4,
'should return 4 when there are several longest streaks (same length)'
);
let cals = [];
const n = 100;
for (var i = 0; i < n; i++) {
cals.push(moment.utc(moment.utc().subtract(i, 'days')).valueOf());
}
t.equal(
calcLongestStreak(prepUniqueDays(cals)),
n,
'should return correct longest streak when there is a very long period'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc(moment.utc().subtract(1, 'days')).valueOf(),
moment.utc(moment.utc().subtract(1, 'hours')).valueOf()
])
),
2,
'should return correct longest streak in default timezone ' +
'UTC given `undefined` timezone'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('9/11/2015 4:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 3:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 1:00', 'M/D/YYYY H:mm').valueOf()
]), PST
),
4,
'should return 4 when there is the only one more-than-one-days-long ' +
'streak available given PST'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
moment.utc('9/11/2015 23:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/12/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/13/2015 2:00', 'M/D/YYYY H:mm').valueOf(),
moment.utc('9/14/2015 6:00', 'M/D/YYYY H:mm').valueOf()
], PST), PST
),
3,
'should return 3 when longest streak is 3 in PST ' +
'(but would be different in default timezone UTC)'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
1453174506164, 1453175436725, 1453252466853, 1453294968225,
1453383782844, 1453431903117, 1453471373080, 1453594733026,
1453645014058, 1453746762747, 1453747659197, 1453748029416,
1453818029213, 1453951796007, 1453988570615, 1454069704441,
1454203673979, 1454294055498, 1454333545125, 1454415163903,
1454519128123, moment.tz(PST).valueOf()
], PST),
PST
),
17,
'should return 17 when there is no break in PST ' +
'(but would be break in UTC) and it is current'
);
t.equal(
calcLongestStreak(
prepUniqueDays([
1453174506164, 1453175436725, 1453252466853, 1453294968225,
1453383782844, 1453431903117, 1453471373080, 1453594733026,
1453645014058, 1453746762747, 1453747659197, 1453748029416,
1453818029213, 1453951796007, 1453988570615, 1454069704441,
1454203673979, 1454294055498, 1454333545125, 1454415163903,
1454519128123, moment.utc().valueOf()
])
),
4,
'should return 4 when there is a break in UTC (but no break in PST)'
);
});
test.onFinish(() => {
clock.restore();
});
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