| 
									
										
										
										
											2019-08-26 21:52:47 +03:00
										 |  |  | // For more tutorials: https://blog.learngoprogramming.com | 
					
						
							|  |  |  | // | 
					
						
							|  |  |  | // Copyright © 2018 Inanc Gumus | 
					
						
							|  |  |  | // Learn Go Programming Course | 
					
						
							|  |  |  | // License: https://creativecommons.org/licenses/by-nc-sa/4.0/ | 
					
						
							|  |  |  | // | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | package main | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | import ( | 
					
						
							|  |  |  | 	"sort" | 
					
						
							|  |  |  | ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | type group struct { | 
					
						
							|  |  |  | 	sum  map[string]result // metrics per group key | 
					
						
							|  |  |  | 	keys []string          // unique group keys | 
					
						
							|  |  |  | 	key  groupFunc | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | func groupBy(key groupFunc) *group { | 
					
						
							|  |  |  | 	return &group{ | 
					
						
							|  |  |  | 		sum: make(map[string]result), | 
					
						
							|  |  |  | 		key: key, | 
					
						
							|  |  |  | 	} | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | // digest the results | 
					
						
							|  |  |  | func (g *group) digest(results iterator) error { | 
					
						
							|  |  |  | 	return results.each(func(r result) { | 
					
						
							|  |  |  | 		k := g.key(r) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 		if _, ok := g.sum[k]; !ok { | 
					
						
							|  |  |  | 			g.keys = append(g.keys, k) | 
					
						
							|  |  |  | 		} | 
					
						
							|  |  |  | 
 | 
					
						
							| 
									
										
										
										
											2019-08-28 12:46:43 +03:00
										 |  |  | 		g.sum[k] = r.sum(g.sum[k]) | 
					
						
							| 
									
										
										
										
											2019-08-26 21:52:47 +03:00
										 |  |  | 	}) | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | // each yields the grouped results | 
					
						
							|  |  |  | func (g *group) each(yield resultFn) error { | 
					
						
							|  |  |  | 	sort.Strings(g.keys) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	for _, k := range g.keys { | 
					
						
							|  |  |  | 		yield(g.sum[k]) | 
					
						
							|  |  |  | 	} | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	return nil | 
					
						
							|  |  |  | } |