add: json encoding/decoding quiz and exercises

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Inanc Gumus
2019-05-09 14:10:09 +03:00
parent f8e5056e7a
commit 80cf86da6d
6 changed files with 466 additions and 1 deletions

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@ -176,3 +176,55 @@ fmt.Println(m.title, "&", m.item.title)
> **4:** Right! `m.title` returns "avengers: end game" because the outer type always takes priority. However, `m.item.title` returns "midnight in paris" because you explicitly get it from the inner type: item.
>
## What is a field tag?
1. It allows Go to index struct fields more efficiently
2. You can use it for documenting your code
3. It's like a comment
4. Associates metadata about the field *CORRECT*
> **4:** Correct. For example, the json package can read and encode/decode depending on the associated metadata.
## Which one is correct about a field tag?
1. It needs to be typed according to some rules
2. You can change it to a different value in runtime
3. It's just a string value, and it doesn't have a meaning on its own *CORRECT*
> **1:** This is true to some extent but it can have any value.
>
> **2:** Fields tags are part of a struct type definition so you cannot change their value in runtime.
>
> **3:** Right! It's just a string value. It's only meaningful when other code reads it. For example, the json package can read it and encode/decode depending on the field tag's value.
>
## What is wrong with the following program?
```go
type movie struct {
title string `json:"title"`
}
m := movie{"black panthers"}
encoded, _ := json.Marshal(m)
fmt.Println(string(encoded))
```
1. `movie` is unexported so you cannot encode
2. `title` is unexported so you cannot encode *CORRECT*
3. Error handling is missing so you cannot encode
> **1:** The json package can encode a struct even though its type is unexported.
>
> **2:** Right! The json package can only encode exported fields.
>
> **3:** It's better to handle errors but it's not the main problem here.
>
## Why do you need to pass a pointer to the Unmarshal function?
1. To make it work faster and efficient
2. So it can update the value on memory *CORRECT*
3. To prevent errors
> **2:** Otherwise, it would not be able to update the given value. It's because, every value in Go is passed by value. So a function can only change the copy, not the original value. However, through a pointer, a function can change the original value.