82 lines
1.7 KiB
Go
82 lines
1.7 KiB
Go
// Copyright © 2018 Inanc Gumus
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// Learn Go Programming Course
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// License: https://creativecommons.org/licenses/by-nc-sa/4.0/
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//
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// For more tutorials : https://learngoprogramming.com
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// In-person training : https://www.linkedin.com/in/inancgumus/
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// Follow me on twitter: https://twitter.com/inancgumus
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/*
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✅ #1- Get and check the input
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✅ #2- Create a byte buffer and use it as the output
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✅ #3- Write input to the buffer as it is and print it
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✅ #4- Detect the link
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✅ #5- Mask the link
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✅ #6- Stop masking when whitespace is detected
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✅ #7- Put a http:// prefix in front of the masked link
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*/
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package main
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import (
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"fmt"
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"os"
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)
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const (
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link = "http://"
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nlink = len(link)
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mask = '*'
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)
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func main() {
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args := os.Args[1:]
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if len(args) != 1 {
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fmt.Println("gimme somethin' to mask!")
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return
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}
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var (
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text = args[0]
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size = len(text)
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buf = make([]byte, 0, size)
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in bool
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)
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for i := 0; i < size; i++ {
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// slice the input and look for the link pattern
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// do not slice it when it goes beyond the input text's capacity
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if len(text[i:]) >= nlink && text[i:i+nlink] == link {
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// set the flag: we're in a link! -> "http://....."
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in = true
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// add the "http://" manually
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buf = append(buf, link...)
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// jump to the next character after "http://"
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i += nlink
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}
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// get the current byte from the input
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c := text[i]
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// disable the link detection flag
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// this will prevent masking the rest of the bytes
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switch c {
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case ' ', '\t', '\n': // try -> unicode.IsSpace
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in = false
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}
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// if we're in the link detection mode (inside the link bytes)
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// then, mask the current character
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if in {
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c = mask
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}
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buf = append(buf, c)
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}
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// print out the buffer as text (string)
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fmt.Println(string(buf))
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}
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