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keygen: add more mnemonic language support (#12944)

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This commit is contained in:
guanqun
2020-10-17 10:51:53 +08:00
committed by GitHub
parent 8aecea6d05
commit 4451042c76
2 changed files with 39 additions and 2 deletions
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19
clap-utils/src/keypair.rs
View File

@@ -298,7 +298,24 @@ pub fn keypair_from_seed_phrase(
keypair_from_seed_phrase_and_passphrase(&seed_phrase, &passphrase)?
} else {
let sanitized = sanitize_seed_phrase(seed_phrase);
let mnemonic = Mnemonic::from_phrase(&sanitized, Language::English)?;
let parse_language_fn = || {
for language in &[
Language::English,
Language::ChineseSimplified,
Language::ChineseTraditional,
Language::Japanese,
Language::Spanish,
Language::Korean,
Language::French,
Language::Italian,
] {
if let Ok(mnemonic) = Mnemonic::from_phrase(&sanitized, *language) {
return Ok(mnemonic);
}
}
Err("Can't get mnemonic from seed phrases")
};
let mnemonic = parse_language_fn()?;
let passphrase = prompt_passphrase(&passphrase_prompt)?;
let seed = Seed::new(&mnemonic, &passphrase);
keypair_from_seed(seed.as_bytes())?

22
keygen/src/keygen.rs
View File

@@ -270,6 +270,15 @@ fn main() -> Result<(), Box<dyn error::Error>> {
.takes_value(true)
.help("Specify the number of words that will be present in the generated seed phrase"),
)
.arg(
Arg::with_name("language")
.long("language")
.possible_values(&["english", "chinese-simplified", "chinese-traditional", "japanese", "spanish", "korean", "french", "italian"])
.default_value("english")
.value_name("LANGUAGE")
.takes_value(true)
.help("Specify the mnemonic lanaguage that will be present in the generated seed phrase"),
)
.arg(
Arg::with_name("no_passphrase")
.long("no-passphrase")
@@ -430,7 +439,18 @@ fn do_main(matches: &ArgMatches<'_>) -> Result<(), Box<dyn error::Error>> {
let word_count = value_t!(matches.value_of("word_count"), usize).unwrap();
let mnemonic_type = MnemonicType::for_word_count(word_count)?;
let mnemonic = Mnemonic::new(mnemonic_type, Language::English);
let language = match matches.value_of("language").unwrap() {
"english" => Language::English,
"chinese-simplified" => Language::ChineseSimplified,
"chinese-traditional" => Language::ChineseTraditional,
"japanese" => Language::Japanese,
"spanish" => Language::Spanish,
"korean" => Language::Korean,
"french" => Language::French,
"italian" => Language::Italian,
_ => unreachable!(),
};
let mnemonic = Mnemonic::new(mnemonic_type, language);
let passphrase = if matches.is_present("no_passphrase") {
NO_PASSPHRASE.to_string()
} else {