2021-06-15 00:49:18 -07:00
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---
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id: 5900f5131000cf542c510024
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2022-03-04 19:46:29 +05:30
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title: 'Problema 421: fattori primi di n15+1'
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2021-06-15 00:49:18 -07:00
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challengeType: 5
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forumTopicId: 302091
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dashedName: problem-421-prime-factors-of-n151
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---
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# --description--
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2022-03-04 19:46:29 +05:30
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Numeri nella forma $n^{15} + 1$ sono compositi per ogni numero intero $n > 1$.
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2022-03-04 19:46:29 +05:30
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Per numeri interi positivi $n$ e $m$, sia $s(n, m)$ la somma dei distinti fattori primi di $n^{15} + 1$ non eccedenti $m$.
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2021-06-15 00:49:18 -07:00
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2022-03-04 19:46:29 +05:30
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Ad es. $2^{15} + 1 = 3 × 3 × 11 × 331$.
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Quindi $s(2, 10) = 3$ e $s(2, 1000) = 3 + 11 + 331 = 345$.
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Inoltre ${10}^{15} + 1 = 7 × 11 × 13 × 211 × 241 × 2161 × 9091$.
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Quindi $s(10, 100) = 31$ e $s(10, 1000) = 483$.
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Trova $\sum s(n, {10}^8)$ per $1 ≤ n ≤ {10}^{11}$.
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2021-06-15 00:49:18 -07:00
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# --hints--
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2022-03-04 19:46:29 +05:30
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`primeFactorsOfN15Plus1()` dovrebbe restituire `2304215802083466200`.
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2021-06-15 00:49:18 -07:00
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```js
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assert.strictEqual(primeFactorsOfN15Plus1(), 2304215802083466200);
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```
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# --seed--
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## --seed-contents--
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```js
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function primeFactorsOfN15Plus1() {
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return true;
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}
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2022-03-04 19:46:29 +05:30
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primeFactorsOfN15Plus1();
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```
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# --solutions--
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```js
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// solution required
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```
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