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---
id: 5900f3b11000cf542c50fec4
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title: 'Problema 69: Totiente máximo'
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challengeType: 5
forumTopicId: 302181
dashedName: problem-69-totient-maximum
---
# --description--
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A função Totiente de Euler, ${\phi}(n)$ (às vezes chamada de função phi), é usada para determinar a quantidade de números menores que `n` , que são primos próximos de `n` . Por exemplo, 1, 2, 4, 5, 7 e 8 são todos inferiores a nove e primos relativos de nove, ${\phi}(9) = 6$.
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< div style = 'margin-left: 4em;' >
| $n$ | $\text{Relatively Prime}$ | $\displaystyle{\phi}(n)$ | $\displaystyle\frac{n}{{\phi}(n)}$ |
| --- | ------------------------- | ------------------------ | ---------------------------------- |
| 2 | 1 | 1 | 2 |
| 3 | 1,2 | 2 | 1.5 |
| 4 | 1,3 | 2 | 2 |
| 5 | 1,2,3,4 | 4 | 1.25 |
| 6 | 1,5 | 2 | 3 |
| 7 | 1,2,3,4,5,6 | 6 | 1.1666... |
| 8 | 1,3,5,7 | 4 | 2 |
| 9 | 1,2,4,5,7,8 | 6 | 1.5 |
| 10 | 1,3,7,9 | 4 | 2.5 |
< / div >
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Aqui, vemos que `n` = 6 produz um máximo $\displaystyle\frac{n}{{\phi}(n)}$, onde `n` ≤ 10.
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Calcule o valor de `n` ≤ `limit` onde $\displaystyle\frac{n}{{\phi(n)}}$ é um máximo.
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# --hints--
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`totientMaximum(10)` deve retornar um número.
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```js
assert(typeof totientMaximum(10) === 'number');
```
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`totientMaximum(10)` deve retornar `6` .
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```js
assert.strictEqual(totientMaximum(10), 6);
```
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`totientMaximum(10000)` deve retornar `2310` .
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```js
assert.strictEqual(totientMaximum(10000), 2310);
```
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`totientMaximum(500000)` deve retornar `30030` .
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```js
assert.strictEqual(totientMaximum(500000), 30030);
```
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`totientMaximum(1000000)` deve retornar `510510` .
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```js
assert.strictEqual(totientMaximum(1000000), 510510);
```
# --seed--
## --seed-contents--
```js
function totientMaximum(limit) {
return true;
}
totientMaximum(10);
```
# --solutions--
```js
function totientMaximum(limit) {
function getSievePrimes(max) {
const primesMap = new Array(max).fill(true);
primesMap[0] = false;
primesMap[1] = false;
const primes = [];
for (let i = 2; i < max ; i = i + 2 ) {
if (primesMap[i]) {
primes.push(i);
for (let j = i * i; j < max ; j = j + i ) {
primesMap[j] = false;
}
}
if (i === 2) {
i = 1;
}
}
return primes;
}
const MAX_PRIME = 50;
const primes = getSievePrimes(MAX_PRIME);
let result = 1;
for (let i = 0; result * primes[i] < limit ; i + + ) {
result *= primes[i];
}
return result;
}
```