2018-10-10 18:03:03 -04:00
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---
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id: 5900f4ff1000cf542c510011
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2020-12-16 00:37:30 -07:00
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title: 问题402:整数值多项式
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: problem-402-integer-valued-polynomials
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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可以证明,对于每个整数n,多项式n4 + 4n3 + 2n2 + 5n是6的倍数。还可以显示6是满足该属性的最大整数。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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将M(a,b,c)定义为最大m,使得n4 + an3 + bn2 + cn是所有整数n的m的倍数。例如,M(4,2,5)= 6。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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此外,将S(N)定义为所有0 <a,b,c≤N的M(a,b,c)之和。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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我们可以验证S(10)= 1972和S(10000)= 2024258331114。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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设Fk为斐波纳契数列:对于k≥2,F0 = 0,F1 = 1且Fk = Fk-1 + Fk-2。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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求最高9位数为ΣS(Fk)为2≤k≤1234567890123。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`euler402()`应返回356019862。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(euler402(), 356019862);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function euler402() {
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return true;
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}
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euler402();
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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// solution required
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```
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