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---
id: 5a23c84252665b21eecc7e84
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title: Greatest subsequential sum
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challengeType: 5
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forumTopicId: 302278
2021-01-13 03:31:00 +01:00
dashedName: greatest-subsequential-sum
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---
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# --description--
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Given a sequence of integers, find a continuous subsequence which maximizes the sum of its elements, that is, the elements of no other single subsequence add up to a value larger than this one.
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An empty subsequence is considered to have the sum of \\( 0 \\); thus if all elements are negative, the result must be the empty sequence.
# --hints--
`maximumSubsequence` should be a function.
```js
assert(typeof maximumSubsequence == 'function');
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```
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`maximumSubsequence([ 1, 2, -1, 3, 10, -10 ])` should return an array.
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```js
assert(Array.isArray(maximumSubsequence([1, 2, -1, 3, 10, -10])));
```
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`maximumSubsequence([ 1, 2, -1, 3, 10, -10 ])` should return `[ 1, 2, -1, 3, 10 ]` .
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```js
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assert.deepEqual(maximumSubsequence([1, 2, -1, 3, 10, -10]), [1, 2, -1, 3, 10]);
```
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`maximumSubsequence([ 0, 8, 10, -2, -4, -1, -5, -3 ])` should return `[ 0, 8, 10 ]` .
```js
assert.deepEqual(maximumSubsequence([0, 8, 10, -2, -4, -1, -5, -3]), [
0,
8,
10
]);
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```
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`maximumSubsequence([ 9, 9, -10, 1 ])` should return `[ 9, 9 ]` .
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```js
assert.deepEqual(maximumSubsequence([9, 9, -10, 1]), [9, 9]);
```
`maximumSubsequence([ 7, 1, -5, -3, -8, 1 ])` should return `[ 7, 1 ]` .
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```js
assert.deepEqual(maximumSubsequence([7, 1, -5, -3, -8, 1]), [7, 1]);
```
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`maximumSubsequence([ -3, 6, -1, 4, -4, -6 ])` should return `[ 6, -1, 4 ]` .
```js
assert.deepEqual(maximumSubsequence([-3, 6, -1, 4, -4, -6]), [6, -1, 4]);
```
`maximumSubsequence([ -1, -2, 3, 5, 6, -2, -1, 4, -4, 2, -1 ])` should return `[ 3, 5, 6, -2, -1, 4 ]` .
```js
assert.deepEqual(maximumSubsequence([-1, -2, 3, 5, 6, -2, -1, 4, -4, 2, -1]), [
3,
5,
6,
-2,
-1,
4
]);
```
# --seed--
## --seed-contents--
```js
function maximumSubsequence(population) {
}
```
# --solutions--
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```js
function maximumSubsequence(population) {
function sumValues(arr) {
var result = 0;
for (var i = 0, len = arr.length; i < len ; i + + ) {
result += arr[i];
}
return result;
}
var greatest;
var maxValue = 0;
for (var i = 0, len = population.length; i < len ; i + + ) {
for (var j = i; j < = len; j++) {
var subsequence = population.slice(i, j);
var value = sumValues(subsequence);
if (value > maxValue) {
maxValue = value;
greatest = subsequence;
};
}
}
return greatest;
}
```