41 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
		
		
			
		
	
	
			41 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
|   | --- | ||
|  | title: Iterate Through All an Array's Items Using For Loops | ||
|  | --- | ||
|  | ## Iterate Through All an Array's Items Using For Loops
 | ||
|  | 
 | ||
|  | ## Hint 1
 | ||
|  | - A nested ``for`` loop must be used to search through every element in the array. | ||
|  | ```javascript | ||
|  |  for (let i = 0; i < arr.length; i++) { | ||
|  | ```` | ||
|  | ## Hint 2
 | ||
|  | - Every element of the array must then be compared to the `elem` parameter passed through the `filteredArray()` function. | ||
|  | ```javascript | ||
|  | if (arr[i].indexOf(elem)==-1){ | ||
|  | ``` | ||
|  | ## Hint 3
 | ||
|  | - If a match is NOT found then `newArr` have that entire subarray added. The `push()` function is very useful here.  | ||
|  | ```javascript | ||
|  | newArr.push(arr[i]); | ||
|  | ``` | ||
|  | - Once that entire subarray is added to `newArr` the loop continue with the next element. | ||
|  | 
 | ||
|  | ## Solution:
 | ||
|  | ```javascript | ||
|  | function filteredArray(arr, elem) { | ||
|  |   let newArr = []; | ||
|  |   // change code below this line | ||
|  |    | ||
|  |  for (let i = 0; i < arr.length; i++) {  | ||
|  |     if (arr[i].indexOf(elem)==-1){ //Checks every parameter for the element and if is NOT there continues the code | ||
|  |           newArr.push(arr[i]); //Inserts the element of the array in the new filtered array | ||
|  |             }; | ||
|  |           }; | ||
|  | 
 | ||
|  |   // change code above this line | ||
|  |   return newArr; | ||
|  | }; | ||
|  | // change code here to test different cases: | ||
|  | console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3)); | ||
|  | ``` |