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---
title: 'Problem 9: Special Pythagorean triplet'
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---
# Problem 9: Special Pythagorean triplet
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---
## Problem Explanation
- In this challenge we need to find the pythagorean triple.
- We have the following information - `a < b < c`
- Based on this, we can make a loop starting from `a = 0` and `b = a` since `a < b` always.
- We also know that `a + b + c = n` and `a^2 + b^2 = c^2`, since we have `a`, `b` and `n`. We can find `c` and see if it satisfies the triplet theorem.
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---
## Solutions
<details><summary>Solution 1 (Click to Show/Hide)</summary>
```js
function specialPythagoreanTriplet(n) {
let sumOfabc = n;
for (let a = 1; a < n; a++) {
for (let b = a; b < n; b++) {
let c = n - a - b;
if (c > 0) {
if (c ** 2 == a ** 2 + b ** 2) {
return a * b * c;
}
}
}
}
}
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specialPythagoreanTriplet(1000);
```
#### Relevant Links
- [Wikipedia](https://en.wikipedia.org/wiki/Pythagorean_triple)
</details>