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2018-10-12 15:37:13 -04:00
---
title: Balanced brackets
---
# Balanced brackets
2018-10-12 15:37:13 -04:00
---
## Solutions
2018-10-12 15:37:13 -04:00
<details><summary>### Solution #1 (Click to Show/Hide)</summary>
```js
function isBalanced(str) {
if (str === "") return true;
str = str.split("");
let stack = [];
for (let i = 0; i < str.length; i++) {
if (str[i] === "[") {
stack.push("[");
} else if (str[i] === "]" && stack[stack.length - 1] === "[") {
stack.pop();
}
}
return stack.length === 0;
}
```
#### Code Explanation
- Split the input string into individual characters & loop over them.
- Push every `[` into a stack.
- Check if the item stored on the stack is `[` when a `]` occurs. This makes it a pair & `[` can be removed from the stack.
- The brackets are balanced if there is no item present in the stack.
</details>