100 lines
2.1 KiB
Markdown
100 lines
2.1 KiB
Markdown
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---
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title: Sum to 100
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---
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# Sum to 100
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---
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## Solutions
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<details><summary>Solution 1 (Click to Show/Hide)</summary>
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```javascript
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function sumTo100(n) {
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var permutationsWithRepetition = function(n, as) {
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return as.length > 0 ?
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foldl1(curry(cartesianProduct)(as), replicate(n, as)) : [];
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};
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var cartesianProduct = function(xs, ys) {
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return [].concat.apply([], xs.map(function(x) {
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return [].concat.apply([], ys.map(function(y) {
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return [
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[x].concat(y)
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];
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}));
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}));
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};
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var curry = function(f) {
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return function(a) {
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return function(b) {
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return f(a, b);
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};
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};
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};
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var flip = function(f) {
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return function(a, b) {
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return f.apply(null, [b, a]);
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};
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};
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var foldl1 = function(f, xs) {
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return xs.length > 0 ? xs.slice(1)
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.reduce(f, xs[0]) : [];
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};
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var replicate = function(n, a) {
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var v = [a],
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o = [];
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if (n < 1) return o;
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while (n > 1) {
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if (n & 1) o = o.concat(v);
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n >>= 1;
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v = v.concat(v);
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}
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return o.concat(v);
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};
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var asSum = function(xs) {
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var dct = xs.reduceRight(function(a, sign, i) {
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var d = i + 1; // zero-based index to [1-9] positions
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if (sign !== 0) {
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// Sum increased, digits cleared
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return {
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digits: [],
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n: a.n + sign * parseInt([d].concat(a.digits)
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.join(''), 10)
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};
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} else return { // Digits extended, sum unchanged
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digits: [d].concat(a.digits),
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n: a.n
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};
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}, {
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digits: [],
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n: 0
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});
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return dct.n + (
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dct.digits.length > 0 ? parseInt(dct.digits.join(''), 10) : 0
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);
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};
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var asString = function(xs) {
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var ns = xs.reduce(function(a, sign, i) {
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var d = (i + 1)
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.toString();
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return sign === 0 ? a + d : a + (sign > 0 ? '+' : '-') + d;
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}, '');
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return ns[0] === '+' ? tail(ns) : ns;
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};
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var universe = permutationsWithRepetition(9, [0, 1, -1])
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.filter(function(x) {
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return x[0] !== 1 && asSum(x) === n;
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}).map(asString);
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return universe.sort()
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}
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```
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</details>
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