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							|  |  |  |  | id: 5900f3e71000cf542c50fefa | 
					
						
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										 |  |  |  | title: '問題 123:素數平方餘數' | 
					
						
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										 |  |  |  | challengeType: 5 | 
					
						
							|  |  |  |  | forumTopicId: 301750 | 
					
						
							|  |  |  |  | dashedName: problem-123-prime-square-remainders | 
					
						
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							|  |  |  |  | # --description--
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										 |  |  |  | 令 $p_n$ 爲第 $n$ 個素數:2, 3, 5, 7, 11, ...,並令 $r$ 爲當 ${(p_n−1)}^n + {(p_n+ 1)}^n$ 除以 ${p_n}^2$ 的餘數。 | 
					
						
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										 |  |  |  | 例如,當 $n = 3, p_3 = 5$,$4^3 + 6^3 = 280 ≡ 5\\ mod\\ 25$。 | 
					
						
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										 |  |  |  | 餘數超過 $10^9$ 的 $n$ 的最小值是 7037。 | 
					
						
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										 |  |  |  | 求餘數超過 $10^{10}$ 時的 $n$ 的最小值。 | 
					
						
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							|  |  |  |  | # --hints--
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										 |  |  |  | `primeSquareRemainders()` 應該返回 `21035`。 | 
					
						
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							|  |  |  |  | ```js | 
					
						
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										 |  |  |  | assert.strictEqual(primeSquareRemainders(), 21035); | 
					
						
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										 |  |  |  | ``` | 
					
						
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							|  |  |  |  | # --seed--
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							|  |  |  |  | ## --seed-contents--
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							|  |  |  |  | ```js | 
					
						
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										 |  |  |  | function primeSquareRemainders() { | 
					
						
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							|  |  |  |  |   return true; | 
					
						
							|  |  |  |  | } | 
					
						
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										 |  |  |  | primeSquareRemainders(); | 
					
						
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										 |  |  |  | ``` | 
					
						
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							|  |  |  |  | # --solutions--
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							|  |  |  |  | ```js | 
					
						
							|  |  |  |  | // solution required | 
					
						
							|  |  |  |  | ``` |