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								title: Completing the Square
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
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								## Completing the Square
 
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
											2018-10-15 02:57:50 +01:00 
										
									 
								 
							 
							
								
									
										 
									 
								
							 
							
								 
							 
							
							
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											2019-03-07 18:47:48 -08:00 
										
									 
								 
							 
							
								
									
										 
									 
								
							 
							
								 
							 
							
							
								The completing the square method is one of the many methods for solving a < a  href = 'https://guide.freecodecamp.org/mathematics/quadratic-equations'  target = '_blank' > quadratic equation< / a > . It involves changing the form of the equation so that the left side becomes a perfect square.
							 
						 
					
						
							
								
									
										
										
										
											2018-10-04 14:47:55 +01:00 
										
									 
								 
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								A quadratic equation generally takes the form: < em > ax< sup > 2< / sup >  + bx + c< / em >  = 0. To solve the above, follow these steps: 
							 
						 
					
						
							
								
									
										
										
										
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								1.  Move the constant value to the Right Hand Side of the equation so it becomes: < br >  
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								< pre > < em > ax< sup > 2< / sup >  + bx = -c< / em > < / pre > 
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								2.  Make the coefficient of x< sup > 2</ sup >  equal to 1 by dividing both sides of the equation by < em > a</ em >  so that we now have: < br >  
							 
						 
					
						
							
								
									
										
										
										
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								< pre > x< sup > 2< / sup >  + (< sup > b< / sup > /< sub > a< / sub > )x = -(< sup > c< / sup > /< sub > a< / sub > )< / pre > 
							 
						 
					
						
							
								
									
										
										
										
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								3.  Next, add the square of half of the coefficient of the < em > x</ em > -term to both sides of the equation: < br >  
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								< pre > x< sup > 2< / sup >  + (< sup > b< / sup > /< sub > a< / sub > )x  + (< sup > b< / sup > /< sub > 2a< / sub > )< sup > 2< / sup >  = (< sup > b< / sup > /< sub > 2a< / sub > )< sup > 2< / sup >  - (< sup > c< / sup > /< sub > a< / sub > )< / pre > 
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								4.  Completing the square on the Left Hand Side and simplifying the Right Hand Side of the above equation, we have:
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								< pre > (x< sup > < / sup >  + < sup > b< / sup > /< sub > 2a< / sub > )< sup > 2< / sup >  = (< sup > b< sup > 2< / sup > < / sup > /< sub > 4a< sup > 2< / sup > < / sub > ) - (< sup > c< / sup > /< sub > a< / sub > )< / pre > 
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								5.  Further simplifying the Right Hand Side, 
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								< pre > (x< sup > < / sup >  + < sup > b< / sup > /< sub > 2a< / sub > )< sup > 2< / sup >  = (b< sup > 2< / sup >  - 4ac) ÷  4a< sup > 2< / sup >  < / pre > 
							 
						 
					
						
							
								
									
										
										
										
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								6.  Finding the square root of both sides of the equation, 
							 
						 
					
						
							
								
									
										
										
										
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								< pre > x< sup > < / sup >  + < sup > b< / sup > /< sub > 2a< / sub >  = ± ((b< sup > 2< / sup >  - 4ac)< sup > ½ < / sup >  ÷  2a) < / pre > 
							 
						 
					
						
							
								
									
										
										
										
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								7.  By making x the subject of our formula, we are able to solve for its value completely:
							 
						 
					
						
							
								
									
										
										
										
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								< pre > x< sup > < / sup >  = (-b ±  (b< sup > 2< / sup >  - 4ac)< sup > ½ < / sup > ) ÷  2a < / pre > 
							 
						 
					
						
							
								
									
										
										
										
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								*  [Varsity Tutors ](https://www.varsitytutors.com/hotmath/hotmath_help/topics/completing-the-square )
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								*  [Maths is Fun ](https://www.mathsisfun.com/algebra/completing-square.html )
							 
						 
					
						
							
								
									
										
										
										
											2018-10-04 14:47:55 +01:00