feat: Add guide article and update its challenge (#36371)
* feat: Add guide article and update its challenge * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * fix: Stop hints from being hidden * fix: Improve the wording. * Update index.md Fixed per suggestion * Update index.md Fixed per suggestion
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Quincy Larson
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---
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title: Replace Loops using Recursion
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---
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# Replace Loops using Recursion
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### Hint 1:
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When `n <= 0` `sum(arr, n)` returns `arr[0]`.
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### Hint 2:
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When `n` is larger than 0 `sum(arr, n)` returns `sum(arr, n - 1) + arr[n]`
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## Basic code solution:
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<details><summary>(Click to reveal)</summary>
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```js
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function sum(arr, n) {
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if (n <= 0) {
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return arr[0];
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} else {
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return sum(arr, n - 1) + arr[n];
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}
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}
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```
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</details>
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### Code explanation
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The `if` statement checks to see if `sum` is evaluating the base case, `n <= 0`, or not. If it is, then `sum` returns the answer, `arr[0]` - the sum of elements from 0 to 0 inclusive. Otherwise it recurses by evaluating a simpler function call, `sum(arr, n - 1)`. Once that returns it adds a single array element, `arr[n]`, to it and returns that sum.
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### Resources
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- [Recursive Functions - *MDN JavaScript reference*](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Functions#Recursion)
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