* feat: Add guide article and update its challenge * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * fix: Stop hints from being hidden * fix: Improve the wording. * Update index.md Fixed per suggestion * Update index.md Fixed per suggestion
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title
title |
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Replace Loops using Recursion |
Replace Loops using Recursion
Hint 1:
When n <= 0
sum(arr, n)
returns arr[0]
.
Hint 2:
When n
is larger than 0 sum(arr, n)
returns sum(arr, n - 1) + arr[n]
Basic code solution:
(Click to reveal)
function sum(arr, n) {
if (n <= 0) {
return arr[0];
} else {
return sum(arr, n - 1) + arr[n];
}
}
Code explanation
The if
statement checks to see if sum
is evaluating the base case, n <= 0
, or not. If it is, then sum
returns the answer, arr[0]
- the sum of elements from 0 to 0 inclusive. Otherwise it recurses by evaluating a simpler function call, sum(arr, n - 1)
. Once that returns it adds a single array element, arr[n]
, to it and returns that sum.