feat: Add guide article and update its challenge (#36371)
* feat: Add guide article and update its challenge * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * Update guide/english/certifications/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion/index.md Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com> * fix: Stop hints from being hidden * fix: Improve the wording. * Update index.md Fixed per suggestion * Update index.md Fixed per suggestion
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			@@ -7,7 +7,7 @@ videoUrl: 'https://www.freecodecamp.org/news/how-recursion-works-explained-with-
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## Description
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					## Description
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<section id='description'>
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					<section id='description'>
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Recursion is the concept that a function can be expressed in terms of itself. To help understand this, start by thinking about the following task: multiply the first <code>n</code> elements in an array to create the product of the elements. Using a <code>for</code> loop, you could do this:
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					Recursion is the concept that a function can be expressed in terms of itself. To help understand this, start by thinking about the following task: multiply the elements from <code>0</code> to <code>n</code> inclusive in an array to create the product of those elements. Using a <code>for</code> loop, you could do this:
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```js
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					```js
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  function multiply(arr, n) {
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					  function multiply(arr, n) {
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@@ -31,7 +31,7 @@ However, notice that <code>multiply(arr, n) == multiply(arr, n - 1) * arr[n]</co
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  }
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					  }
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```
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					```
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The recursive version of <code>multiply</code> breaks down like this. In the <dfn>base case</dfn>, where <code>n <= 0</code>, it returns the result, <code>arr[0]</code>. For larger values of <code>n</code>, it calls itself, but with <code>n - 1</code>. That function call is evaluated in the same way, calling <code>multiply</code> again until <code>n = 0</code>.  At this point, all the functions can return and the original <code>multiply</code> returns the answer.  
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					The recursive version of <code>multiply</code> breaks down like this. In the <dfn>base case</dfn>, where <code>n <= 0</code>, it returns the result, <code>arr[0]</code>. For larger values of <code>n</code>, it calls itself, but with <code>n - 1</code>. That function call is evaluated in the same way, calling <code>multiply</code> again until <code>n = 0</code>.  At this point, all the functions can return and the original <code>multiply</code> returns the answer.
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<strong>Note:</strong> Recursive functions must have a base case when they return without calling the function again (in this example, when <code>n <= 0</code>), otherwise they can never finish executing.
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					<strong>Note:</strong> Recursive functions must have a base case when they return without calling the function again (in this example, when <code>n <= 0</code>), otherwise they can never finish executing.
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@@ -40,7 +40,7 @@ The recursive version of <code>multiply</code> breaks down like this. In the <df
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## Instructions
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					## Instructions
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<section id='instructions'>
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					<section id='instructions'>
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Write a recursive function, <code>sum(arr, n)</code>, that creates the sum of the first <code>n</code> elements of an array <code>arr</code>.
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					Write a recursive function, <code>sum(arr, n)</code>, that returns the sum of the elements from <code>0</code> to <code>n</code> inclusive in an array <code>arr</code>.
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</section>
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					</section>
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					---
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					title: Replace Loops using Recursion
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					---
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					# Replace Loops using Recursion
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					### Hint 1:
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					When `n <= 0` `sum(arr, n)` returns `arr[0]`.
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					### Hint 2:
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					When `n` is larger than 0 `sum(arr, n)` returns `sum(arr, n - 1) + arr[n]`
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					## Basic code solution:
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					<details><summary>(Click to reveal)</summary>
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					```js
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					function sum(arr, n) {
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					  if (n <= 0) {
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					    return arr[0];
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					  } else {
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					    return sum(arr, n - 1) + arr[n];
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					  }
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					}
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					```
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					</details>
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					### Code explanation
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					The `if` statement checks to see if `sum` is evaluating the base case, `n <= 0`, or not.  If it is, then `sum` returns the answer, `arr[0]` - the sum of elements from 0 to 0 inclusive.  Otherwise it recurses by evaluating a simpler function call, `sum(arr, n - 1)`.  Once that returns it adds a single array element, `arr[n]`, to it and returns that sum.
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					### Resources
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					- [Recursive Functions - *MDN JavaScript reference*](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Functions#Recursion)
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